Answer:
28.1 m/s
Explanation:
= Initial velocity of the fish = 1.52 m/s
y = Height of the bird = 40 m
= Acceleration in y axis = 
= Initial velocity in y axis = 0
The final velocity in x direction will remain the same as the initial velocity as there is no acceleration in the x direction 
Resultant velocity is given by
The fish is moving at a velocity of 28.1 m/s when it hits the water.
As we can see here the lever has two forces at two ends
1. 300 N
2. 200 N
now we need to find the Torque on the lever about the fulcrum
so we will have
1. clockwise torque due to force at right end is
2. counterclockwise torque due to force at left end
so as per above calculations we can see that net torque on the lever is clockwise as it has more torque in clockwise direction
so <u>it will rotate clockwise</u>
Answer:
Explanation:
We shall apply conservation of momentum along x and y axis.
Let the final momentum of second particle be p₁ along x axis and p₂ along y axis.
Considering momentum along x axis
2 + 0 = 3 cos 45 + p₁
p₁ = 2-2.12 = - 0.12 kg m/s
Considering momentum along y axis
4 + 0 = 3 sin 45 + p₂
p₂ = 4-2.12 = 1.88 kg m/s
Final momentum = √ ( p₁² + p₂² )
=√ ( .12² + 1.88² )
= 1.88 approx
Answer:
The correct answer is d. tension pneumothorax.
Explanation:
The increasing build-up of air that is in the pleural space is what we call the tension pneumothorax and this happens due to the lung laceration that lets the air to flee inside the pleural space but it does not return.
<u>ANY</u> pair of vectors can produce that resultant, as long as ...
If one of the vectors is V₁ = A i + B j . . . . . . where 'A' and 'B' are <u>any</u> two numbers,
then the other one is V₂ = -A i - B j
