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Ivanshal [37]
3 years ago
8

Whats 6 3/7 ×1 5/9.

Physics
2 answers:
aniked [119]3 years ago
7 0
6 3/7 * 1 5/9
45/7 * 14/9
630/63
10
tatyana61 [14]3 years ago
6 0
That would most likely be 10
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A cave rescue team lifts an injured spelunker directly upward and out of a sinkhole by means of a motor-driven cable. The lift i
bija089 [108]

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Mass m = 78 kg

Vertical height in each stage h = 11 m

(a).

Initial speed u = 0

Final speed v = 1.1 m / s

v^2=u^2 + 2 as

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a = 0.055 m/s²

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W_a = 8455.59 J

(b).Work done

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W_b = 78× 9.8× 11

W_b= 8408.4 J

c)

Work done

W= m g h + \dfrac{1}{2}m(v_f-v_i)^2

Where V = final speed

               = 0

            v = 1.1 m / s

for deceleration a = -0.055 m/s²

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F_L = 56 (-0.055+9.8) = 545.72 N

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3 years ago
The closest stars are 4 light years away from us. How far away must you be from a 854 kHz radio station with power 50.0 kW for t
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The distance from the radio station is 0.28 light years away.

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As per the question:

Distance, d = 4 ly

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Power, P = 50 kW = 50\times 10^{3}\ W

I_{p} = 1\ photon/s/m^{2}

Now,

From the relation:

P = nhf

where

n = no. of photons/second

h = Planck's constant

f = frequency

Now,

n = \frac{P}{hf} = \frac{50\times 10^{3}}{6.626\times 10^{- 34}\times 854\times 10^{3}} = 8.836\times 10^{31}\ photons/s

Area of the sphere, A = 4\pi r^{2}

Now,

Suppose the distance from the radio station be 'r' from where the intensity of the photon is 1\ photon/s/m^{2}

I_{p} = \frac{n}{A} = \frac{n}{4\pi r^{2}}

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r = \sqrt{\frac{8.836\times 10^{31}}{4\pi}} = 2.65\times 10^{15}\ m

Now,

We know that:

1 ly = 9.4607\times 10^{15}\ m

Thus

r = \frac{2.65\times 10^{15}}{9.4607\times 10^{15}} = 0.28\ ly

5 0
3 years ago
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