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3 years ago

Which numbers are arranged in order from least to greatest?

Mathematics

2 answers:

Sidana [21]3 years ago

8 0

The last answer is correct

Virty [35]2 years ago

6 0

The last answer because 16% would equal .16 so therefore the answer is D

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Help me with my test

pychu [463]

Answer:

Step-by-step explanation:

5 0

2 years ago

Which is equal to (2+3i)+(-4+i)? A, -2-4i B, -2-2i C, -2+2i D, -2+4i E, 6+4i

inysia [295]

Answer:

D. -2+4i

Step-by-step explanation:

just combine like terms :)

6 0

2 years ago

Read 2 more answers

A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la

SOVA2 [1]

Answer:

$8\pi\text{ square cm}$

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

$S=2\pi rh$

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

$4^2 = (2r)^2 + h^2$ ( see in the below diagram ),

$16 = 4r^2 + h^2$

$16 - 4r^2 = h^2$

$\implies h=\sqrt{16-4r^2}$

Thus, the surface area of the cylinder,

$S=2\pi r(\sqrt{16-4r^2})$

Differentiating with respect to r,

$\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})$

$=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})$

$=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})$

Again differentiating with respect to r,

$\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})$

For maximum or minimum,

$\frac{dS}{dt}=0$

$2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0$

$-8r^2 + 16 = 0$

$8r^2 = 16$

$r^2 = 2$

$\implies r = \sqrt{2}$

Since, for r = √2,

$\frac{d^2S}{dt^2}=negative$

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

$S = 2\pi (\sqrt{2})(\sqrt{16-8})$

$=2\pi (\sqrt{2})(\sqrt{8})$

$=2\pi \sqrt{16}$

$=8\pi\text{ square cm}$

4 0

2 years ago

Solve the equations: bx-c=ax+d

Paladinen [302]

Answer:

$x = \frac{c + d}{b - a}$

Step-by-step explanation:

bx-c=ax+d

<=> bx-ax=c+d

<=> (b-a)x=c+d

<=> x=(c+d)/(b-a)

8 0

2 years ago

Minutes Studying

GalinKa [24]

Must it be a scatterplot or no?

7 0

2 years ago

Read 2 more answers