Answer:
the function given 
for 4 units up, just add 4 as a constant
4 units up means, every old value will now be 4 more than previous value. at x=0, y=0 in the transformed curse it should x=0 and y=4, so just add it.

for 6 units left,
each old value of y should now occur 6 units before the old value of x i.e. X=x+6
for example, the point (0,0) should occur at (-6,0) in the transformed graph,
hence, 
so the final curve is

Answer:
(2,5)
Step-by-step explanation:
The rule to 90 degrees about the origin is (x,y) to (-y,x). You basically switch the values of y and x but remember the value of y is negative. The value of y is -2 so -2 is now 2 since the rule changed the sign (-2×-y=2) and 5 isnt affected except it is the x value. Just know that since they r switched, x is now 2 and y is 5 when rotated 90 degrees about the origin.
So here, ABCD is being inscribed in a circle, so ABCD is a cyclic quadrilateral (as inscribed in a circle) also, there exists a property of cyclic quadrilateral, i.e, the sum of opposite angles of a cyclic quadrilateral is 180°, so we can just write the following equation using this :





Divide both sides by
:

Substitute
, so that
.

Multiply both sides by
:

The left side can be condensed into the derivative of a product.

Integrate both sides to get

Solve for
:

Solve for
:

![\implies\boxed{y(x)=\sqrt[3]{\dfrac14x^2e^x(2\ln x-1)+Ce^x}}](https://tex.z-dn.net/?f=%5Cimplies%5Cboxed%7By%28x%29%3D%5Csqrt%5B3%5D%7B%5Cdfrac14x%5E2e%5Ex%282%5Cln%20x-1%29%2BCe%5Ex%7D%7D)
I may be wrong, but it seems as if it's fully simplified...