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Paha777 [63]
3 years ago
14

Consider the parametric equations

Mathematics
1 answer:
MArishka [77]3 years ago
5 0

Answer:(a)x^2+2y^2=2

(b)In the attached diagram

Step-by-step explanation:Step 1: Multiply both equations by t

xt=t(cost -sint)\\ty\sqrt{2} =t(cost +sint)

Step 1:  Multiply both equations by t

xt=t(cost -sint)\\ty\sqrt{2} =t(cost +sint)

Step 2:We square both equations

(xt)^2=t^2(cost -sint)^2\\(ty)^2(\sqrt{2})^2 =t^2(cost +sint)^2

Step 3: Adding the two equations

(xt)^2+(ty)^2(\sqrt{2})^2=t^2(cost -sint)^2+t^2(cost +sint)^2\\t^2(x^2+2y^2)=t^2((cost -sint)^2+(cost +sint)^2)\\x^2+2y^2=(cost -sint)^2+(cost +sint)^2\\(cost -sint)^2+(cost +sint)^2=2\\x^2+2y^2=2 hopes this helps

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Answer: c.(3, 25) and (7, 9)

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3 years ago
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Answer:

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2 years ago
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