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2 years ago

Consider the parametric equations

Mathematics

1 answer:

MArishka [77]2 years ago

5 0

Answer:(a)x^2+2y^2=2

(b)In the attached diagram

Step-by-step explanation:Step 1: Multiply both equations by t

xt=t(cost -sint)\\ty\sqrt{2} =t(cost +sint)

Step 1: Multiply both equations by t

xt=t(cost -sint)\\ty\sqrt{2} =t(cost +sint)

Step 2:We square both equations

(xt)^2=t^2(cost -sint)^2\\(ty)^2(\sqrt{2})^2 =t^2(cost +sint)^2

Step 3: Adding the two equations

(xt)^2+(ty)^2(\sqrt{2})^2=t^2(cost -sint)^2+t^2(cost +sint)^2\\t^2(x^2+2y^2)=t^2((cost -sint)^2+(cost +sint)^2)\\x^2+2y^2=(cost -sint)^2+(cost +sint)^2\\(cost -sint)^2+(cost +sint)^2=2\\x^2+2y^2=2 hopes this helps

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allsm [11]

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Now let us find the 4 disks that will result in a range of 7.

Range = highest number – lowest number

The pair of highest and lowest number that will result in range of 7 is: (1 & 8), (2 & 9), (3 & 10)

As a basis of calculation, let us use the pair 1 & 8.

There are four possible ways to select 1 and three for 8.

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Arrangements of maximum and minimum pair=12

Now we need to calculate for the remaining 2 disk. There are 6 numbers between 1 & 8. The total possibilities for selecting 2 disk from the remaining 6 is:

Possibilities of selecting 2 disk from remaining 6 = 6 * 5

Possibilities of selecting 2 disk from remaining 6 = 30

Therefore, the total possibility to get a range of 7 from a pair of 1 & 8 is:

Total possibility for a pair = 12 * 30

Total possibility for a pair = 360

Since there are a total of three pairs (1 & 8), (2 & 9), (3 & 10):

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Therefore:

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2 years ago

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Answer:

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lianna [129]

The given statement is proved by side-angle-side (SAS) theorem.

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Hence, The given statement is proved by side-angle-side (SAS) theorem.

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2 years ago

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