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Kruka [31]
3 years ago
11

if polygon MAST with coordinates M(-3,-1), A(-3,2),S (-1,3) and t (1,1) is reflected across x=-3, then which of the following co

ordinates represent the vertices of the polygon MAN'S'? select all that apply

Mathematics
2 answers:
MrRissso [65]3 years ago
7 0

Answer with explanation:

→The Polygon MAST has coordinates "M(-3,-1), A(-3,2),S (-1,3) T (1,1)".

Now, the polygon is reflected across , line ,x= -3.

Now, the Meaning of reflection is that ,the Shape and size of Image before and after Reflection does not change.

And when you , reflect the polygon which is a quadrilateral having vertices M, A, S, and T, the perpendicular distance from line , x=-3, from each of the vertices of the Quadrilateral,Called Pre-Image, will be same from each of the Vertices of the polygon after Reflection Called Image.

When , "polygon MAST is reflected across line", x=-3, the vertices of Image M'A'S'T' will be

M(-3,-1)→M'(-3,-1)

A(-3,2)→A'(-3,-2)

S(-1,3)→S'(-5,3)

T(1,1)→T'(-7,1)

Nookie1986 [14]3 years ago
3 0

Let 'a' be the point and 'A' be the reflection of point 'a' through line x= -3

we know, (a+A)/2 (mid point of line aA) should lie on line x= -3

so by using this, we calculate vertices of reflected shape of MAST, we get

(-3,-1), (-3,2),(-5,3) and (-7,1)


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Is matrix multiplication comutative?
konstantin123 [22]

Answer:

Matrix multiplication is not conmutative

Step-by-step explanation:

The matrix multiplication can be performed if the number of columns of the first matrix is equal to the number of rows of the second matrix

Let A with dimension mxn and B with dimension nxp represent two matrix

The multiplication of A by B is a matrix C with dimension mxp, but the multiplication of B by A is can't be calculated because the number of columns of B is not the number of rows of A. Therefore, you can notice that is not conmutative in general.

But even if the multiplication of AB and BA is defined (For example if A and B are squared matrix of 2x2) the multiplication is not necessary conmutative.

The matrix multiplication result is a matrix which entries are given by dot product of the corresponding row of the first matrix and the corresponding column of the second matrix:

A=\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\\B= \left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\\AB = \left[\begin{array}{ccc}a11b11+a12b21&a11b12+a12b22\\a21b11+a22b21&a21b12+a22b22\end{array}\right]\\\\BA=\left[\begin{array}{ccc}b11a11+b12a21&b11a12+b12a22\\b21a11+b22ba21&b21a12+b22a22\end{array}\right]

Notice that in general, the result is not the same. It could be the same for very specific values of the elements of each matrix.

6 0
3 years ago
5. If position of object x = 3 sinΘ – 7 cosΘ then motion of object is bounded between position.​
lesya692 [45]

9514 1404 393

Answer:

  ±√58 ≈ ±7.616

Step-by-step explanation:

The linear combination of sine and cosine functions will have an amplitude that is the root of the sum of the squares of the individual amplitudes.

  |x| = √(3² +7²) = √58

The motion is bounded between positions ±√58.

_____

Here's a way to get to the relation used above.

The sine of the sum of angles is given by ...

  sin(θ+c) = sin(θ)cos(c) +cos(θ)sin(c)

If this is multiplied by some amplitude A, then we have ...

  A·sin(θ+c) = A·sin(θ)cos(c) +A·cos(θ)sin(c)

Comparing this to the given expression, we find ...

  A·cos(c) = 3   and   A·sin(c) = -7

We know that sin²+cos² = 1, so the sum of the squares of these values is ...

  (A·cos(c))² +(A·sin(c))² = A²(cos(c)² +sin(c)²) = A²(1) = A²

That is, A² = (3)² +(-7)² = 9+49 = 58. This tells us the position function can be written as ...

  x = A·sin(θ +c) . . . . for some angle c

  x = (√58)sin(θ +c)

This has the bounds ±√58.

3 0
3 years ago
Please please help me again, I really need help and thank you.
ipn [44]

Answer:

Perimeter of Compound Shapes: Composite Rectangles. Perimeter is the total distance around the outside of a shape. horizontal. sides must be the same length in total as the one longer red side.

Step-by-step explanation:Also not sure...Hope this kinda helps...

5 0
3 years ago
Simplify x²-49/3x+21
Vera_Pavlovna [14]
First, you factor and simplify (respectively) the numerator and denominator. Your equation becomes:

\frac{(x-7)(x+7)}{3(x + 7)}

Notice, there is a (x + 7) on both the top and the bottom. Because of this, they cancel each other out. What is left is your answer:

\frac{(x-7)}{3}

3 0
3 years ago
Read 2 more answers
49 POINTS!!!!!!!!
belka [17]
The answer is II and III, which is the last choice from above.  This is because the symbol "less than (or equal to)" indicated a conjunction, which means we have to take into account that the absolute value can be less than or equal to 15, and greater than or equal to -15.  This solution set falls in between the two values, hence, the conjunction.
3 0
3 years ago
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