Question

A nonideal gas is confined to a constant volume container

Answer 1

Answer:

$W=0$

Explanation:

This is a process done at constant volume and therefore, all the heat added to the system is used to increase the internal energy of the gas (both pressure and temperature)

Also, the work if calculared by:

$W=\int_{V_1}^{V_2}P*dV$

If dV=0

$W=0$