Answer:
addition of aqueous hydrochloric acid
Explanation:
The solubility of copper (ll) hydroxide in water is negligible. This implies that the substance is only slightly soluble in water.
However, the addition of aqueous hydrochloric acid leads to the following reaction;
Cu(OH)2 + 2HCl ---------> CuCl2 + 2H2O
Copper II chloride is soluble in water hence the crystals dissolve when stirred. and the molar solubility increases.
And the answer is equivalent to 0.64 moles of CO2.
It will help you
Answer:
The answer to your question is a) N₂ b) 3.04 g of NH₃
Explanation:
Data
mass of H₂ = 2.5 g
mass of N₂ = 2.5 g
molar mass H₂ = 2.02 g
molar mass of N₂ = 28.02 g
molar mass of NH₃ = 17.04 g
Balanced chemical reaction
3H₂ + 1 N₂ ⇒ 2NH₃
A)
Calculate the theoretical yield 3H₂ / N₂ = 3(2.02) / 28.02 = 0.22
Calculate the experimental yield H₂/N₂ = 2.5/2.5 = 1
Conclusion
The limiting reactant is N₂ (nitrogen) because the experimental proportion was higher than the theoretical proportion.
B)
28.02 g of N₂ -------------------- (2 x 17.04) g of NH₃
2.5 g of N₂ -------------------- x
x = (2.5 x 2 x 17.04) / 28.02
x = 85.2 / 28.02
x = 3.04 g of NH₃
It is a homogenous solution because the powder is suspended in the liquid and there is no difference between any parts of it.
Electrons, specifically valence electrons