Let
and
be these consecutive integers. For some base
, we can write
![(x_{10})^2=220_b=2b^2+2b](https://tex.z-dn.net/?f=%28x_%7B10%7D%29%5E2%3D220_b%3D2b%5E2%2B2b)
![((x+1)_{10})^2=251_b=2b^2+5b+1](https://tex.z-dn.net/?f=%28%28x%2B1%29_%7B10%7D%29%5E2%3D251_b%3D2b%5E2%2B5b%2B1)
If
![x^2=2b^2+2b](https://tex.z-dn.net/?f=x%5E2%3D2b%5E2%2B2b)
then
![x^2+1=2b^2+2b+1](https://tex.z-dn.net/?f=x%5E2%2B1%3D2b%5E2%2B2b%2B1)
Now,
![x^2+2x+1=2b^2+5b+1](https://tex.z-dn.net/?f=x%5E2%2B2x%2B1%3D2b%5E2%2B5b%2B1)
![2x+2b^2+2b+1=2b^2+5b+1](https://tex.z-dn.net/?f=2x%2B2b%5E2%2B2b%2B1%3D2b%5E2%2B5b%2B1)
![\implies2x=3b](https://tex.z-dn.net/?f=%5Cimplies2x%3D3b)
Squaring both sides gives
![4x^2=9b^2](https://tex.z-dn.net/?f=4x%5E2%3D9b%5E2)
and so
![4(2b^2+2b)=9b^2](https://tex.z-dn.net/?f=4%282b%5E2%2B2b%29%3D9b%5E2)
![\implies8b^2+8b=9b^2](https://tex.z-dn.net/?f=%5Cimplies8b%5E2%2B8b%3D9b%5E2)
![\implies b^2-8b=0\implies\boxed{b=8}](https://tex.z-dn.net/?f=%5Cimplies%20b%5E2-8b%3D0%5Cimplies%5Cboxed%7Bb%3D8%7D)
(because the base has to be non-zero)
Answer: $169,500
Step-by-step explanation:
The mean simply means the average price of a set of a numbers that are given. For one t calculate the mean, one has to add the numbers that are given and then divide them by the amount of numbers.
I'm the case above, the numbers given are $165,000, $188,000, $175,000, and $150,000.
Mean = ($165,000 ,+ $188,000 +$175,000 + $150,000) ÷ 4
= $678,000/4
= $169,500
B. 250 cm3 hope this helps
Answer:
t = 4
Step-by-step explanation:
Given
+ 3 = 5 ( subtract 3 from both sides )
= 2
Multiply both sides by 2 to clear the fraction
t = 2 × 2 = 4
Answer:
a little bit of a very nice and smart and k liye kuch bhi nahi ha ha bol rahe hai