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DanielleElmas [232]
3 years ago
6

Find the geometric mean of the pair of numbers. 96 and 6

Mathematics
2 answers:
sineoko [7]3 years ago
6 0
Id multiply the numbers and take the square root X<span>2=96×6=576</span><span>→X=<span>576<span>−−−</span>√</span>→X=24</span>Hence Geometric mean of the given numbers is 24.
Anton [14]3 years ago
4 0

Answer:

Geometric mean is  24.

Step-by-step explanation:

Given : Numbers 96 and 6.

To find : Find the geometric mean of the pair of numbers.

Solution : We have given that  96 and 6.

Geometric mean : The Geometric Mean is the average where we multiply the numbers together and then take a square root (for two numbers), cube root (for three numbers) etc.

Then

Geometric mean  : First we multiply them: 96 × 6 = 576.

Now take the square root: √576 = 24.

Therefore, Geometric mean is  24.

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If p(x)=2x^2-4 and q(x)=x-3, what is (p•q)(x)
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p(q(x)) = 2(x - 3)^2 - 4

Expand (x - 3)^2.

p(q(x)) = 2(x^2 - 6x + 9) - 4

p(q(x)) = 2x^2 - 12x + 14

6 0
3 years ago
The sum of 3 consecutive odd numbers is 51. What is the second number in this sequence?
tatiyna
(2n +1) + (2n + 3) + (2n + 5) = 51
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numbers are 15 17 and 19

5 0
3 years ago
What is the answer to this problem? Ignore the work. What is the correct answer?
yan [13]

Answer:

c = 42.5

Step-by-step explanation:

The legs of the triangle are a and b and the hypotenuse is c

Let a be the shorter leg

The hypotenuse is 5 more than the longest leg

c = b+5

The shortest leg is 20

a = 20

We can use the Pythagorean theorem

a^2 +b^2 = c^2

Substituting in what we know from above

20 ^2 + b^2 = (b+5)^2

FOIL  (b+5)^2 = b^2 +5b+5b +25 = b^2+10b+25

400 + b^2 = b^2+10b+25

Subtract b^2 from both sides

400+b&2-b^2 = b^2 -b^2 +10b+25

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Subtract 25 from both sides

400-25 = 10b+25-25

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Divide by 10

375/10 = 10b/10

37.5 = b

But we want to find c

c=b+5

c = 37.5+5

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6 0
3 years ago
an NFL team kicker misses 2 out of every 11 field goals if he missed 8 filed goals throughout the season how many did he attempt
Aleks [24]
For this equation, you want to do it in fractions/ratios to properly solve it. You would have his average misses out of every field goal and his real missed attempts over total. It would look like this

\frac{2}{11}  =   \frac{8}{x}

You want to solve for x since x is the total amount of field goals that he attempted. You can do this by doing cross multiplication:

(2)(x) = (8)(11)

From here you can get:

2x = 88

Divide each side by 2 to isolate x and you get:

x=  44

So he made a total of 44 field goals.
3 0
3 years ago
Read 2 more answers
Plz help me on this quick
Studentka2010 [4]

Answer: The third one

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7 0
2 years ago
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