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3 years ago

The ph of a solution containing 0.818 M acetic acid (ka1.76*10-5) ans 0.172 M sodium acetate is?

Chemistry

1 answer:

kvasek [131]3 years ago

5 0

Explanation:

It is known that the relation between pH and $pK_{a}$ is as follows.

pH = $pK_{a} + log \frac{[salt]}{[acid]}$

and, $pK_{a} = -log K_{a}$

Hence, first we will calculate the value of $pK_{a}$ as follows.

$pK_{a} = -log K_{a}$

= $-log (1.76 \times 10^{-5}$

= 4.75

Now, we will calculate the value of pH as follows.

pH = $pK_{a} + log \frac{[\text{sodium acetate}]}{\text{acetic acid}}$

= $4.75 + log \frac{0.172}{0.818}$

= 4.75 + (-0.677)

= 4.07

Therefore, we can conclude that the pH of given solution is 4.07.

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LuckyWell [14K]

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3 years ago

Isotopes of an element have the same number of ________ and different numbers of ________. neutrons... protons protons... neutro

Ivahew [28]

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2 years ago

Calculate the number of pounds of CO2CO2 released into the atmosphere when a 22.0 gallon22.0 gallon tank of gasoline is burned i

Gnesinka [82]

Answer:

391.28771 pounds of carbon-dioxide was released into the atmosphere when 22.0 gallon tank of gasoline is burned in an automobile engine.

Explanation:

Density of the gasoline ,d= 0.692 g/mL

Volume of gasoline in an tanks,V = 22.0 gallons = 83,279.02 mL

Let mass of the gasoline be M

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M = V × d = 83,279.02 mL × 0.692 g/mL=57,629.081 g

Given that gasoline is primarily octane.

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$

Mass of octane burnt in the tank = M = 57,629.081 g

Moles of octane = $\frac{57,629.081 g}{114.08g/mol}=505.1637 mol$

According to reaction, 2 moles of octane gives 16 moles of carbon-dioxide.

Then 505.1637 mol of octane will give:

$\frac{16}{2}\times 505.1637 mol=4,041.3100 mol$ of carbon-dioxide

Mass of 4,041.3100 mol of carbon-dioxide:

4,041.3100 mol × 44.01 g/mol = 177,858.05 g

Mass of carbon-dioxide produced in pounds = 391.28771 pounds

391.28771 pounds of carbon-dioxide was released into the atmosphere when 22.0 gallon tank of gasoline is burned in an automobile engine.

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3 years ago

Zinc reacts with aqueous sulfuric acid to form hydrogen gas: zn(s) h2so4(aq) ? znso4(aq) h2(g) in an experiment, 201 ml of wet h

WINSTONCH [101]

The products of reaction are ZnSO4 and H2. Since ZnSO4 is in aqueous form (aq), therefore only H2 and water vapor contributes to the overall total pressure in the system.
Total Pressure = 764 torr = H2 partial pressure + Water partial pressure
Since Water partial pressure is 26.74 torr so,
H2 partial pressure = 737.26 torr = 0.97 atm

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3 years ago

How many molecules of co2 form when 2.00 g of c2h5oh are produced?

Ronch [10]

The reaction involved in this problem is called the combustion reaction where a hydrocarbon reacts with oxygen to product carbon dioxide and water. The reaction of C2H5OH would be as follows:

C2H5OH + 3O2 = 2CO2 + 3H2O

To determine the number of molecules of CO2 that is formed, we need to determine the number of moles produced from the initial amount of C2H5OH and the relation from the reaction. Then we multiply avogadros number which is equal to 6.022x10^23 molecules per mole.

2.00 g C2H5OH ( 1 mol C2H5OH / 46.08 g C2H5OH ) ( 2 mol CO2 / 1 mol C2H5OH ) = 0.0868 mol CO2
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4 0

3 years ago