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2 years ago

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How many grams of aluminum chloride are needed to react completely with 1.084g lithium sulfide?

1 answer:

Oksi-84 [34.3K]2 years ago

5 0

Molar mass :

Li₂S = <span>45.947 g/mol

AlCl</span>₃ = <span>133.34 g/mol

</span><span>3 Li</span>₂<span>S + 2 AlCl</span>₃<span> = 6 LiCl + Al</span>₂S₃

3 * 45.947 g Li₂S ----------> 2 * <span>133.34 g AlCl</span>₃
1.084 g Li₂S ----------------> ?

Mass Li₂S = 1.084 * 2 * 133.34 / 3 * 45.947

Mass Li₂S = 289.08112 / 137.841

Mass Li₂S = 2.0972 g

hope this helps!

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