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deff fn [24]
3 years ago
7

How do you solve -(6yz) with an exponent of -2 and x with exponent of 0

Mathematics
1 answer:
anastassius [24]3 years ago
5 0

Idk

Step-by-step explanation:

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Solve the following equation when a = 3 and b = 2.<br> 5a^2 − 10b + 9b =
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The answer for this problem is 43
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1 yard

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the formula for the circumference of a circle is 2 times pi times the radius of the circle. so to find out the radius you divide the circumference by 2 and then by pi.

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Simplify 6f+5g-3f+3g
VARVARA [1.3K]

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Chelsey wants to join a fitness club. The fitness club charges an initial membership fee of $55 and a monthly fee of $19.50. She
Kay [80]
So if you have to pay 55 out front and then continue to pay 19.50 monthly the equation will look like this:
19.50*m + 55 = x
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She has 250 dollars to spend so add that in for x
<span>19.50*m + 55 = 250. 
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4 0
3 years ago
Without a calculator how would you solve this?
mina [271]

Answer:

the largest number that is less than (2+√3)^6 is 2701

Step-by-step explanation:

\bigstar \ (2+\sqrt{3})^6= \\\\C{}^{0}_{6}2^{6}+C{}^{1}_{6}2^{5}\sqrt{3}^1+C{}^{2}_{6}2^{4}\sqrt{3}^2+C{}^{3}_{6}2^{3}\sqrt{3}^3+C{}^{4}_{6}2^{2}\sqrt{3}^4+C{}^{5}_{6}2^{1}\sqrt{3}^5+C{}^{6}_{6}\sqrt{3}^6

=64+192\sqrt{3}+720 +480\sqrt{3} +540+108\sqrt{3} +27\\=1351+780\sqrt{3}

\bigstar\  (2-\sqrt{3} )^6 =\\\\1351-780\sqrt{3}

\bigstar\  \bigstar\  (2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =\\\\1351+780\sqrt{3}+1351-780\sqrt{3}

\Longrightarrow(2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =2702

\Longrightarrow(2+\sqrt{3} )^6 =2702-(2-\sqrt{3} )^6

0 < \left( 2-\sqrt{3} \right) < 1 \Longrightarrow 0 < \left( 2-\sqrt{3} \right)^{6} < 1 \Longrightarrow-1 < \left( 2-\sqrt{3} \right)^{6} < 0

\Longrightarrow2702-1 < 2702-\left( 2-\sqrt{3} \right)^{6} < 2702+0

\Longrightarrow 2701 < \left( 2+\sqrt{3} \right)^{6} < 2702

8 0
2 years ago
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