Answer:
y = -2x + 16
Step-by-step explanation:
So first you plug in the values you know into the slop int. form, equation, in which it is y = mx +b. When you plug in the slope value then you will get the equation of y = -2x +b, in which then you have to solve for the b value.
In order to solve for the b value, you then plug in the x and y values of the coordinate that is given so what you would do is this: 6 = -2(5) +b
6 = -10 +b
16 = b
So then you find out b is 16 in which you just plug back into the equation. So finally you write the equation, y = -2x+16.
since it has a diameter of 28, then its radius must be half that or 14.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=14 \end{cases}\implies A=\pi (14)^2\implies A=196\pi ~\hfill \stackrel{\stackrel{semi-circle}{half~that}}{98\pi }](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D14%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2814%29%5E2%5Cimplies%20A%3D196%5Cpi%20~%5Chfill%20%5Cstackrel%7B%5Cstackrel%7Bsemi-circle%7D%7Bhalf~that%7D%7D%7B98%5Cpi%20%7D)
2(x+6)(x+1)
2x^2 + 14x + 12
2(x^2 + 7x + 6)
2(x+6)(x+1)
Basically thats it
Answer:
-40
20
20
20
Step-by-step explanation:
Answer: D
Step-by-step explanation:
