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koban [17]
3 years ago
11

A fair coin is continually flipped until heads appears for the 10th time. Let X denote the number of tails that occur. Compute t

he probability mass function of X.
Physics
1 answer:
Bond [772]3 years ago
4 0

Answer:

P(X=n) = [n+9 C 9] (0.5)ⁿ⁺¹⁰

Explanation:

Number of times a head appears = 10

Total number of times the coin is flipped = X + 10

X = number of tails

Since it is certain that the last flip is a head , probability mass function of tail can be gotten out of (X + 10 -1) flips = X + 9 flips

P(X=n) = [n+9 C 9] (0.5)ⁿ⁺¹⁰

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A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.
labwork [276]

Answer:

9.4 m/s

Explanation:

According to the work-energy theorem, the work done by external forces on a system is equal to the change in kinetic energy of the system.

Therefore we can write:

W=K_f -K_i

where in this case:

W = -36,733 J is the work done by the parachute (negative because it is opposite to the motion)

K_i = 66,120 J is the initial kinetic energy of the car

K_f is the final kinetic energy

Solving,

K_f = K_i + W=66,120+(-36,733)=29387 J

The final kinetic energy of the car can be written as

K_f = \frac{1}{2}mv^2

where

m = 661 kg is its mass

v is its final speed

Solving for v,

v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.4 m/s

4 0
4 years ago
A parachute on a drag race car opens and changes the velocity of the car from 75 m/s to 45 m/s in 8 seconds. Calculate the avera
nikdorinn [45]
Buscalo en gugal byy
3 0
3 years ago
A 14.0 g wad of sticky clay is hurled horizontally at a 110 g wooden block initially at rest on a horizontal surface. The clay s
ahrayia [7]

Answer:

86.53 m/s

Explanation:

Given:

Mass of clay (m) = 14.0 g = 0.014 kg

Mass of block (M) = 110 g = 0.110 kg

Initial speed of block (U) = 0 m/s

Sliding distance (d) = 7.50 m

Coefficient of friction between block and surface (μ) = 0.650

Let the initial speed of clay be 'u' and speed of clay and block just after collision be 'v'.

Now, momentum is conserved just before and just after collision.

Momentum just before collision = mu + 0 = mu

Momentum just after collision = (m + M)v

Therefore, mu=(M+m)v --------- (1)

Now, using newton's second law and we find the acceleration of the system.

The frictional force is given as:

f=\mu mg=-ma\\\\a=-\mu g

Now, using equation of motion, we can find the velocity just after collision.

0^2=v^2+2ad\\\\v=\sqrt{-2ad}\\\\v=\sqrt{-2\times (-\mu g)\times d}\\\\v=\sqrt{2\mu gd}

Plug in the given values and find 'v'. This gives,

v=\sqrt{2\times 0.650\times 9.8\times 7.50}\\\\v=\sqrt{95.55}=9.77\ m/s

Now, using equation (1) and substituting the given values, we get:

0.014u=(0.014+0.110)\times 9.77\\\\u=\frac{0.124\times 9.77}{0.014}\\\\u=86.53\ m/s

Therefore, the speed of the clay immediately before impact is 86.53 m/s.

7 0
4 years ago
1.
nlexa [21]

Answer:

By using Pythagoras Formula

Explanation:

Measure the distance man is sliding. “It will be c”

Measure the distance of between the tower and a post with which wire is attached. It will be “b”

Then apply Pythagoras Formula c2=a2 + b2 and solve it.

It will give the height of tower.

7 0
3 years ago
13. Litmus paper can be used to determine if a solution is an acid or a base. There are two types of
Over [174]

Answer:

The main use of litmus is to test whether a solution is acidic or basic. Light Blue litmus paper turns red under acidic conditions and red litmus paper turns blue under basic or alkaline conditions, with the color change occurring over the pH range 4.5–8.3 at 25 °C (77 °F). Neutral litmus paper is purple.

Explanation:

7 0
3 years ago
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