All categories

3 years ago

Rhino can run at speed about 28 miles per hour what is the speed in feet per second to the nearst whole number

Mathematics

1 answer:

Savatey [412]3 years ago

5 0

(28 mph) x (5,280 ft/mi) / (60 min/hr) / (60 sec/min) = 41 feet per second

You might be interested in

PLEASE HELP WITH GRAPH LAST QUESTION I NEED

SVETLANKA909090 [29]

Answer:

$\sf g(x) = -1(x+3)^2 -2$

Explanation:

$\sf original \ graph: \ y=-x^{2}$

the graph is translated 3 units to the left and 2 units down.

vertex: (-3,-2) point: (-1,-6)

$\sf so \ new \ graph :$

$\sf y = a(x-h)^2 +k$

$\sf -6 = a(-1-(-3))^2 -2$

$\sf -6 = 4a -2$

$\sf 4a = -4$

$\sf a = -1$

$\sf equation:$

$\sf y = a(x-h)^2 +k$

$\sf y = -1(x+3)^2 -2$

6 0

3 years ago

Read 2 more answers

Jen classifies the number 4.567 as an irrational number because it does not repeat. Is Jen correct? Explain.

lilavasa [31]

Answer:

Yes

Step-by-step explanation:

That number is irrational because it does not repeat and rational number repeats

3 0

3 years ago

Read 2 more answers

There are 412 students at sunshine middle school. 225 students are in 5th 6th grade and the rest are in 7th or 8th grades. How m

Arada [10]

Answer:

187 students in 7th or 8th grade

17,088 pages

Step-by-step explanation:

412 - 225 is 187.

A dozen is 12

12 x 16 x 89 = 17,088

4 0

3 years ago

The gym offers a discount when more than one member of the family joins. The first member (n=0) pays $550 per year. The second m

Verizon [17]

a. If we subtract 75 from 550 twice, we get 400, which is the third member to join. Subtract 75 from 400, we get $325, the fourth member to join.

b. It is not possible that a member would join for free if it was a large family. 75 does not fit into 550 evenly. You can prove this by solving the expression 550÷75.

c. The lowest amount that a member would pay to join is $25.00. It would be the 7th member.

5 0

3 years ago

What is the surface area of the triangular prism shown?

Lunna [17]

Answer:

The first step that we are going to do is to solve the area of the top rectangle. We are given a width of 15 cm and a length of 25 cm so we can just multiply them against each other to get the area.

$Area = l * w$

$Area = 25\ cm * 15\ cm$

$Area = 375\ cm^2$

The second side that we are going to solve for is the bottom rectangle. We are given a width of 12 cm and a length of 25 cm so lets just multiply them against each other to get the area.

$Area = l * w$

$Area = 25\ cm * 12\ cm$

$Area = 300\ cm^2$

The next area that we are going to determine is the back rectangle which has a width of 9 cm and a length of 25 cm so lets just multiply them against each other to get the area.

$Area = l * w$

$Area = 25\ cm * 9\ cm$

$Area = 225\ cm^2$

The final area that we have to determine are the side triangles. After determining the area of one triangle we will have to multiply it by 2 to get the area for both of the triangles. We are given a base of 12 cm and a height of 9 cm so lets just use the formula to find the area.

$Area = \frac{1}{2}* b*h$