A submarine heads toward a port, which broadcasts a signal at 175 MHz. If the submarine heads toward the port at 46 m/s, what ch
1 answer:
Answer:
Δf = 0.00003 MHz = 30 Hz
Explanation:
The apparent frequency due to the motion of receiver towards the source is given by Doppler's effect, while the source is stationary. Therefore, the formula is given as follows:
where,
f = apparent frequency
c = speed of light = 3 x 10⁸ m/s
v₀ = velocity of observer = 46 m/s
f₀ = Original Frequency = 175 MHz = 175 x 10⁶ Hz
Therefore,
f = 175.00003 MHz
Therefore, the change in frequency is:
Δf = f - f₀
Δf = 175.00003 MHz - 175 MHz
<u>Δf = 0.00003 MHz = 30 Hz</u>
You might be interested in
Answer:
The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).
(C) is correct option.
Explanation:
Given that,
Mass of block = 1.0 kg
Dependent force = F(x)
Frictional force = F(f)
Suppose, the following information would students need to test the hypothesis,
(A) The function F(x) for 0 < x < 5 and the value of F(f).
(B) The function a(t) for the time interval of travel and the value of F(f).
(C) The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).
(D) The function a(t) for the time interval of travel, the time it takes the block to move 5 m, and the value of F(f).
(E) The block's initial velocity, the time it takes the block to move 5 m, and the value of F(f).
We know that,
The work done by a force is given by,
.....(I)
Where, = net force
We know, the net force is the sum of forces.
So,
According to question,
We have two forces F(x) and F(f)
So, the sum of these forces are
Here, frictional force is negative because F(f) acts against the F(x)
Now put the value in equation (I)
We need to find the value of
Using newton's second law
...(II)
We know that,
Acceleration is rate of change of velocity.
Put the value of a in equation (II)
Now, the work done by the net force on the block is,
The work done by the net force on the block is equal to the change in kinetic energy of the block.
Hence, The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).
(C) is correct option.
Explanation:
It is given that,
Radius of loop, r = 78 mm = 0.078 m
Current, I = 114 A
(a) Magnetic field strength of the circular loop is given by :
B = 0.000918 T
or
(b) Energy density at the center of the loop is given by :
Hence, this is the required solution.