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3 years ago

Find the magnitude of the force needed to accelerate a 300 g mass with a⃗ = -0.205 m/s2 i^+0.700 m/s2 j

1 answer:

7 0

F=ma
m=300g= 0.3kg
a= -0.205i +0.700j m/s2 = <-0205, 0.7>m/s2

Thus, F = 0.3<-0.205, 0.7> N
F = <-0.0615, 0.21> N
= -0.0615i N +0.2100j N

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Um corpo de massa 50g recebe 300 calorias e sua temperatura sobe de -10°C até 20°C. Determine a capacidade térmica do corpo e o

kykrilka [37]

The specific heat capacity of the substance is $0.963 J/g^{\circ}C$

Explanation:

When an object of mass m is supplied with a certain amount of energy Q, its temperature increases according to the equation:

$Q=mC_s \Delta T$

where

m is the mass of the object

$C_s$ is its specific heat capacity

$\Delta T$ is the increase in temperature of the object

In this problem, we have

$Q=300 cal \cdot 4.814 = 1444.2 J$

m = 50 g

$\Delta T = 20C-(-10C)=30^{\circ}C$

Therefore, we can solve for $C_s$ to find its specific heat capacity:

$C_s = \frac{Q}{m\Delta T}=\frac{1444.2}{(50)(30)}=0.963 J/gC$

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4 years ago

Provide three statements that demonstrate the importance of units when describing motion

lakkis [162]

Stamina

Speed

Consestancy

3 0

4 years ago

Two very long uniform lines of charge are parallel and are separated by 0.300 m. each line of charge has charge per unit length

Alenkasestr [34]

linear charge density of system of two line charges is given as

$\lambda = 5.20 \muC/m$

now as we know that electric field due to a line charge at some distance from it is given by

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

so here we will first find the electric field of first line charge at the position of other line charge

$E = \frac{5.20 * 10^{-6}}{2 \pi * 8.85 * 10^{-12}* 0.300}$

$E = 312000 N/C$

now as we know that

$F = qE$

here q = charge on the line charge system at which force is required

E = electric field on that system of charge where force is required

now we can find the charge by

$q = \lambda * L$

$q = 5.20 * 10^{-6}* 0.05 = 0.26 * 10^{-6} C$

Now using the above formula

$F = qE$

$F = 0.26 * 10^{-6} * 312000$

$F = 0.0811 N$

so force on the part of wire is F = 0.0811 N

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3 years ago

Which variable is represented by the following symbol? ∑F

mario62 [17]

Answer:

d.Net force

Explanation:

The net force is the force which is the sum of all the forces acting on an object simultaneously.

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3 years ago

Explain how you think global winds can impact weather in an area.

weeeeeb [17]

Answer:

As the wind travels across the earth, air masses and global winds do not travel in straight lines. in the Northern hemisphere air veers to the right and in southern hemisphere to the left. this motion can result in large circulating weather systems, as air blows away from or into a high or low pressure areas.

on earth the main differences in air pressure are caused by differences in temperatures. cool air produces high air pressure and warm air produces low air pressure.

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3 years ago