Position displacement velocity acceleration are vectors and the rest are scalars
The potential energy will be 1.46*10^-4J.
To find the answer, we have to know about the torque acting on a current loop in a uniform magnetic field.
<h3>How to find the potential energy of the loop?</h3>
- We have the expression for torque acting on a current loop in a uniform magnetic field as,

where; M is the magnetic dipole moment, B is the magnetic field , and theta is the angle between M and B.
- As we know that, the torque is equal to force times the perpendicular distance. Thus, it is equivalent to the work done. This work is stored as the potential energy in the loop.
- Thus, the potential energy will be,

Thus, we can conclude that, the potential energy will be 1.46*10^-4J.
Learn more about the torque here:
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Seconds squared is the time unit of acceleration. It represents the change in distance units per second per second. For example, 3 m/sec² means a distance covering 3 meters in the first second, then 9 meters in the 2nd second, and 37 meters in the third second. (3^1, 3^2, 3^3).
Acceleration is part of Newton's 2nd law: force = mass x acceleration. Units of work: joule = kg·m²/s², and power: watts = kg·m²/s³ all contain accelerations.
Stark contrast to paths on energy surfaces or even mechanistic reactions, rule-based and inductive computational approaches to reaction prediction mostly consider only overall transformations. Overall transformations are general molecular graph rearrangements reflecting only the net change of several successive mechanistic reactions. For example, Figure 1 shows the overall transformation of an alkene interacting with hydrobromic acid to yield the alkyl bromide along with the two elementary reactions which compose the transformation.
By looking at how wiggily the bar is lol