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Temka [501]
3 years ago
15

Draw and label a picture or make a real life model of something to display conservation of energy. Make sure it is something tha

t demonstrates going from potential energy to kinetic energy and back again. For example you could draw a roller coaster, make a pendulum, draw a skateboard park or create something else. Be creative! Make sure your work is original! Do not copy and paste from a website or other source. Write a paragraph or story to explain the transformation between potential and kinetic energy as shown in your picture or model. You should have at least 5 complete sentences with a main idea and supporting details. Make sure your work is original! Do not copy and paste from a website or other source. You can turn in your finished project as a video, a Power Point, a Word document, a hand drawn picture and paragraph, or some other form of presentation. Make sure it clearly shows your project and explains the relationship between kinetic and potential energy.

Physics
1 answer:
sweet-ann [11.9K]3 years ago
6 0
The picture shows it has a real life something to display conservation of energy  with kinetic energy and potential energy. 


Five sentences are for potential and kinetic energy. Potential energy is to energy an object when it stores. Kinetic energy is something to motion. When the potential energy is slows down the potential energy it might be increases. As from the object when the speeds up and it is decreases to potential energy.

Kinetic energy is to calculated by KE= mass×velocity²/2 as a fraction.

Potential energy is to calculated by PE= mass×g×height.

And the another picture it has a <span>energy, kinetic energy, mechanical energy, conservation of energy.

</span>

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dAnswer:

Explanation:

5 0
3 years ago
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Vector ~A has a negative x-component 3.07 units in length and a positive y-component 3.17 units in length. When a vector ~B = b1
luda_lava [24]

Answer:

a. 3.07 b. 1.26

Explanation:

Given that A = -3.07i + 3.17j and B = b1i + b1j and C = A + B = 0i + 4.43j

Since A + B = -3.07i + 3.17j + b1i + b2j

= (-3.07 + b1)i + (3.17 + b2)j

So,(-3.07 + b1)i + (3.17 + b2)j = 0i + 4.43j

Comparing components,

-3.07 + b1 = 0 (1) and 3.17 + b2 = 4.43 (2)

a. From (1), b1 = 3.07

b. From(2) b2 = 4.43 - 3.17 = 1.26

4 0
3 years ago
A 265 g mass attached to a horizontal spring oscillates at a frequency of 3.40 Hz . At t =0s, the mass is at x= 6.20 cm and has
lara [203]

Answer:

The phase constant is 7.25 degree  

Explanation:

given data

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frequency = 3.40 Hz

time t = 0 s

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solution

as phase constant is express as

y = A cosФ ..............1

here A is amplitude that is = \sqrt{(\frac{v_x}{\omega })^2+y^2 }  = \sqrt{(\frac{35}{2\times \pi  \times y})^2+6.2^2 }  =  6.25 cm

put value in equation 1

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cosФ  = 0.992

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5 0
3 years ago
12. A frain moves from rest to a speed of 25 m/s in 30.0 seconds. What is its acceleration?
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\\ \tt\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \tt\longmapsto Acceleration=\dfrac{25-0}{30}

\\ \tt\longmapsto Acceleration=\dfrac{25}{30}

\\ \tt\longmapsto Acceleration=0.8m/s^2

6 0
3 years ago
21. A toy car starts from rest and begins to
Bond [772]

Answer:

v = 66 m/s

Explanation:

Given that,

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Let v is the final velocity. It can be calculated using first equation of motion. It is given by :

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v = 66 m/s

So, the final velocity of the car is 66 m/s.

8 0
3 years ago
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