Answer:
time tt = 40.76 s
Explanation:
In this exercise we can find the acceleration time, the speed with which the acceleration ends and the rise and flight time
For all these calculations we can use vertical launch kinematics
The speed for maximum height is zero
v² = v₀² - 2 g y
v₀ = √ 2gy
v₀ = √ (2 9.8 980)
v₀ = 138.59 m / s
The time it takes to climb after finishing the acceleration is
v = v₀ - gt
t₁ = v₀ / g
t₁ = 138.59 / 9.8
t₁ = 14.14 s
The acceleration time is
v = v₀ + a t₂
As part of the rest the initial speed is zero
t₂ = v / a
t₂ = 138.59 / 16
t₂ = 8.66 s
The height raised at this time is
y₂ = v₀ t + ½ a t²
y₂ = 0 + ½ 16 8.66²
y₂ = 600 m
Let's look for the descent time, the height of the rocket is
y = y₂ + y₁
y = 600 + 980
y = 1580 m
y = v₀t + ½ g t²
v₀ = 0
t₃ = √ 2y / g
t₃ = √ (2 1580 / 9.8)
t₃ = 17.96 s
Total flight time is
tt = t₁ + t₂ + t₃
tt = 14.14 + 8.66 + 17.96
tt = 40.76 s
Answer:
a) , b)
Explanation:
a) The acceleration due to gravity inside the planet is:
b) The acceleration at the surface of the planet is:
A rock at the edge of a cliff has potential energy because it isn't in motion, but is located in a place that motion could occur in the near future.
Answer:
A force is a push or pull that acts on an object.
:)
Answer:
9. The Sun's Gravity
10. The core is the densest layer