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sineoko [7]
3 years ago
7

a ball moves at a constant speed of 1/2 meter per second. How much time does it take the ball to move 1 meter?

Physics
1 answer:
lesya [120]3 years ago
4 0

Answer:

2 seconds

Explanation:

if a ball travels 1/2 meter per second, and there's 2 halfs in a whole, 1/2 meter per second x 2 halfs in a whole meter is 2 seconds to travel a meter

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How many balls are there in a ski ball machine?
gtnhenbr [62]

Answer:

i think 2 per each sac

Explanation:

i dont know for sure...

Hope this helps

8 0
2 years ago
A car traveling north with a velocity of 33 m/sec slows down to a velocity of 12 m/sec north within 10 sec. What is the car’s de
strojnjashka [21]

a=v/t

v= 33-12 = 21

21÷10=2.1

a= 2.1

4 0
2 years ago
Read 2 more answers
A sample of n2 gas occupies a volume of 746 ml at stp. What volume would n2 gas occupy at 155 ◦c at a pressure of 368 torr?
musickatia [10]

Answer:

2.41 L

Explanation:

We can solve the problem by using the ideal gas equation, which can be rewritten as:

\frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2}

where we have:

p_1 = 1.01\cdot 10^5 Pa (initial pressure is stp pressure)

V_1 = 746 mL = 0.746 L = 7.46\cdot 10^{-4}m^3 is the initial volume

T_1 = 0^{\circ}=273 K is the initial temperature (stp temperature)

p_2 = 368 torr = 4.9\cdot 10^4 Pa is the final pressure

V_2 = ? is the final volume

T=155^{\circ}=428 K is the final temperature

By substituting the numbers inside the formula and solving for V2, we find the final volume:

V_2 = \frac{p_1 V_1 T_2}{T_1 p_2}=\frac{(1.01\cdot 10^5 Pa)(7.46\cdot 10^{-4} m^3)(428 K)}{(273 K)(4.9\cdot 10^4 Pa)}=2.41\cdot 10^{-3} m^3

which corresponds to 2.41 L.

7 0
3 years ago
7. Sally's mass on Earth is 50 kg. What is her weight on the moon?
Makovka662 [10]

Answer:

82.6

Explanation:

7 0
2 years ago
A ball is released from rest at a height of 10 m and falls freely to the
ElenaW [278]

Answer:

The new kinetic energy would be 16 times greater than before.

Explanation:

Kinetic energy is found using this formula:

  • KE = 1/2mv²
  • where KE = kinetic energy (J), m = mass (kg), and v = velocity (m/s)

We can see that kinetic energy is directly proportional to the square of the velocity, meaning that if the speed was increased by 4 times, then the kinetic energy would get increased by a factor of 16.

The velocity just before the ball hits the ground can be found by the equation:

  • √(2gh)

Let's substitute h = 10 m and h = 40 m into this formula.

  • √(2g(10))
  • √(2g(40))

We can see that the velocity increases by a factor of 4 (10 m → 40 m).

Therefore, this means that the kinetic energy would also be increased by a factor of (4)² = 16. Thus, the answer is D) The new kinetic energy would be 16 times greater than before.

6 0
2 years ago
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