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Phoenix [80]
3 years ago
14

A piece of glass is immersed in a liquid. It proceeds to float on the liquid's surface. This shows that the density of the glass

is _____ the density of the liquid.
a. More than
b. Less than
c. Equal to
d. Not comparable
Chemistry
1 answer:
tamaranim1 [39]3 years ago
7 0

Answer: b) Less dense

Explanation:

Differences in density is one reason objects float or sink.

An object more dense than the fluid in which it is immersed will sink, while objects less dense than the fluid in which it is immersed will float to the surface.

But objects floats at constant level if the density is equal to the density of the fluid in which it is immersed; it neither rises nor sinks in the fluid in this case.

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Why do electrons enter the 4s orbital before entering the 3D orbital
garri49 [273]

The 3d sublevel is not filled until after the 4s sublevel, because the 3d sublevel has more energy than the 4s sublevel, and less energy than the 4p sublevel. (:

8 0
3 years ago
Given the following heats of combustion. CH3OH(l) + 3/2 O2(g) CO2(g) + 2 H2O(l) ΔH°rxn = -726.4 kJ C(graphite) + O2(g) CO2(g) ΔH
sergeinik [125]

Answer:

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

Explanation:

The formation reaction of CH_3OH will be,

C(s)+2H_2(g)+\frac{1}{2}O_2\rightarrow CH_3OH(g),\Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

C(graphite)+O_2(g)\rightarrow CO_2(g), \Delta H_1=-393.5kJ/mole..[1]

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l), \Delta H_2=-285.8kJ/mole..[2]

CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l) , \Delta H_3=-726.4kJ/mole..[3]

Now we will reverse the reaction 3, multiply reaction 2 by 2  then adding all the equations, Using Hess's law:

We get :

C(graphite)+O_2(g)\rightarrow CO_2(g) , \Delta H_1=-393.5kJ/mole..[1]

2H_2(g)+2O_2(g)\rightarrow 2H_2O(l) ,\Delta H_2=2\times (-285.8kJ/mole)=-571.6kJ/mol..[2]

CO_2(g)+2H_2O(l)\rightarrow CH_3OH(g)+\frac{3}{2}O_2(g) ,\Delta H_3=726.4kJ/mole [3]

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+2\times \Delta H_2+\Delta H_3

\Delta H=(-393.5kJ/mole)+(-571.6kJ/mole)+(726.4kJ/mole)

\Delta H=-238.7kJ/mole

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

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3 years ago
What do two or more atoms form when they share electrons in a chemical bond
dlinn [17]
A covalent bond is your answer
6 0
3 years ago
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Ten lab safety rules
Bogdan [553]
Don't touch your eyes.

Never taste-test unless the teacher tells you to.

Do not touch anything without directions.

Wear safety goggles. 

Wash your hands after each experiment.

Wear proper lab clothes.

Do not mishandle lab equipment.

Clean up your workplace.

Act serious; no horseplay!

Report accidents to the teacher right away!


Have a great day, scholar! 
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3 years ago
Analyzing Characteristics of Outer Planets
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Answer:also confused ?

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