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DedPeter [7]
3 years ago
5

Convert 4.5 X 1022 molecules of H2O to moles.

Chemistry
1 answer:
noname [10]3 years ago
3 0

Answer:

<h3>The answer is 0.075 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{4.5 \times  {10}^{22} }{6.02 \times  {10}^{23} }  \\  = 0.074750830...

We have the final answer as

<h3>0.075 moles</h3>

Hope this helps you

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Explanation:

N=Z-A ie. number of neutrons=mass number-atomic number

N=19-9=10

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Write a balanced equation for the reaction<br>between ammonia and sulfuric acid?​
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Explanation:

2NH3+H2SO4→(NH4)2SO4

I hope it'll help you...

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2 years ago
(( PLEASE HELP QUICK ))Which expression can be used to calculate the ratio of the rate of effusion of gas A to the rate of effus
borishaifa [10]

Answer:

The square root of the molar mass of B ÷ the square root of the molar mass of A  

Explanation:

Graham’s Law applies to the effusion of gases:

The rate of effusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

r \propto \dfrac{1}{\sqrt{M}}

If you have two gases A and B, the ratio of their rates of effusion is

\dfrac{r_{\text{A}}}{r_{\text{B}}} = \sqrt{\dfrac{M_{\text{B}}}{M_{\text{A}}}}

3 0
3 years ago
At 350°c, keq = 1.67 × 10-2 for the reversible reaction 2hi (g) ⇌ h2 (g) + i2 (g). what is the concentration of hi at equilibriu
mariarad [96]
According to the reversible reaction equation:

2Hi(g) ↔ H2(g) + i2(g)

and when Keq is the concentration of the products / the concentration of the reactants.

Keq = [H2][i2]/[Hi]^2

when we have Keq = 1.67 x 10^-2

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so, by substitution:

1.67 x 10^-2 = (2.44 x 10^-3)*(7.18x10^-5)/[Hi]^2

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3 years ago
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