3 years ago

How to we measure energy?

Chemistry

2 answers:

WITCHER [35]3 years ago

6 0

With joules hope I helped

Free_Kalibri [48]3 years ago

5 0

Answer:

The official measurement unit for energy is the Joule (J). Among the most common units measuring energy mention should be made of the kilowatt/hour (kWh), used especially for electric energy (in fact it is used to calculate electricity bills).

You might be interested in

Complete this example: A 0.67 molal solution was

Lynna [10]

Answer:

A then C

Explanation:

3 0

2 years ago

Which of the following best explains why the oceanic crust is youngest at the oceanic ridges?

murzikaleks [220]

Answer:

the different depths of the ocean

5 0

3 years ago

Read 2 more answers

Question Ask “ Which Part Of The Ecological Pyramid Is Incorrect.”

shepuryov [24]

Primary producers i believe

4 0

3 years ago

Read 2 more answers

The electrical current in a circuit is measured in which of the following units

ivanzaharov [21]

Answer:

joules

Explanation:

i think

6 0

3 years ago

Read 2 more answers

Calculate the OH− concentration after 53 mL of the 0.100 M KOH has been added to 25.0 mL of 0.200 M HBr. Assume additive vol- um

Andre45 [30]

Answer:

$\large \boxed{\text{0.0038 mol/L}}$

Explanation:

1. Calculate the initial moles of acid and base

$\text{moles of acid} = \text{0.0250 L} \times \dfrac{\text{0.200 mol}}{\text{1 L}} = \text{0.005 00 mol}\\\\\text{moles of base} = \text{0.053 L} \times \dfrac{\text{0.100 mol}}{\text{1 L}} = \text{0.0053 mol}$

2. Calculate the moles remaining after the reaction

OH⁻ + H₃O⁺ ⟶ 2H₂O

I/mol: 0.0053 0.005 00

C/mol: -0.00500 -0.005 00

E/mol: 0.0003 0

We have an excess of 0.0003 mol of base.

3. Calculate the concentration of OH⁻

Total volume = 53 mL + 25.0 mL = 78 mL = 0.078 L

$\text{[OH}^{-}] = \dfrac{\text{0.0003 mol}}{\text{0.078 L}} = \textbf{0.0038 mol/L}\\\\\text{The final concentration of OH$^{-}$ is $\large \boxed{\textbf{0.0038 mol/L}}$}$

8 0

3 years ago