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Yuki888 [10]
3 years ago
5

The Slingshot is a ride for two people. It consists of a single passenger cage, two towers, and two elastic bands. Potential ene

rgy is stored in the elastic bands and the passenger cage is released. On the way up, this potential energy in the elastic bands is converted into the kinetic energy of the cage. At the maximum height of the ride, the energy has been converted into gravitational potential energy of the cage. The slingshot has two towers of height h = 76 m. The towers are a distance d = 31 m apart. Each elastic band has an unstretched length of L0 = 41 m and a spring constant of k = 310 N/m. The total mass of the passengers and cage is m = 410 kg. The car is pulled down to the ground in the middle of the two towers.
Calculate the maximum height, in meters, of the ride.
Physics
1 answer:
Vitek1552 [10]3 years ago
8 0

my bad I was in a herie last time can you please answer my question , I am going to give you the 5 points back for this question and extra 30 points ,

Explanation:

first its going to say 10 points for my question but after that I well make answer a small question and give you 30points. like whats your favorite color . stay tuned .

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Newton's first law of motion is connected with inertia :)
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Read 2 more answers
A 0.10 kg meter stick is held perpendicular to a vertical wall by a 2.5 mm string going from the wall to the far end of the stic
il63 [147K]

Explanation:

a)

Sum of moments = 0 (Equilibrium)

T . cos (Q)*L = m*g*L/2

cos Q = \frac{\sqrt{(2.5^2 - L^2) } }{2.5}

T*\frac{\sqrt{(2.5^2 - L^2) } }{2.5} * L = 0.1 *9.81*L/2

T = \frac{2.4525}{\sqrt{(2.5)^2 - L^2} }

b) If the String is shorter the Q increases; hence, Cos Q decreases which in turn increases Tension in the string due to inverse relationship!

c)

T = \frac{1.962}{\sqrt{(2)^2 - L^2} }

6 0
3 years ago
The function of a microscope is most similar to the function of a.............​
Nataly [62]

Answer:

Magnifying glass and a Petri dish.

Explanation:

4 0
3 years ago
What is the weight of a 2.06 kg text book. show work please
salantis [7]

The weight of anything is (mass) x (gravity in the place where the thing is).

             Gravity on Earth is about 9.8 newtons per kilogram, so on Earth,
             the weight of the book is

                          (2.06 kg) x (9.8 N/kg) = <em>20.19 newtons</em> .


Another way to get around it is:  

               On Earth, 1 kg of mass weighs about 2.205 pounds, so on earth,
               the weight of the book is

                         (2.06 kg) x (2.205 pounds/kg) = <em>4.54 pounds </em>.


7 0
3 years ago
15) A 328-kg car moving at 19.1 m/s in the +x direction hits from behind a second car moving at 13 m/s in the same direction. If
kolbaska11 [484]

Answer:

Explanation:

Given that,

Mass of first car

M1= 328kg

The car is moving in positive direction of x axis with velocity

U1 = 19.1m/s

Velocity of second car

U2 = 13m/s, in the same direction as the first car..

Mass of second car

M2 = 790kg

Velocity of second car after collision

V2 = 15.1 m/s

Velocity of first car after collision

V1 =?

This is an elastic collision,

And using the conservation of momentum principle

Momentum before collision is equal to momentum after collision

P(before) = P(after)

M1•U1 + M2•U2 = M1•V1 + M2•V2

328 × 19.1 + 790 × 13 = 328 × V1 + 790 × 15.1

16534.8 = 328•V1 + 11929

328•V1 = 16534.8—11929

328•V1 = 4605.8

V1 = 4605.8/328

V1 = 14.04 m/s

The velocity of the first car after collision is 14.04 m/s

5 0
3 years ago
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