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3 years ago

A line passes through the points one, four and three, -4 which is the equation of the line

Mathematics

1 answer:

gavmur [86]3 years ago

6 0

ANSWER

$y = - 4x + 8$

EXPLANATION

The given line passes through (1,4) and (3,-4).

The slope of this line is calculated using the formula:

$m =\frac{y_2-y_1}{x_2-x_1}$

We substitute the points into the slope formula to get:

$m = \frac{ - 4 - 4}{3 - 1}$

$\implies \: m = \frac{ - 8}{2}$

$m = - 4$

We substitute the first point and slope into the point-slope formula

$y-y_1=m(x-x_1)$

This implies that

$y - 4 = - 4(x - 1)$

We expand to get

$y - 4 = - 4x + 4$

$y = - 4x + 2/4+ 4$

$y = - 4x + 8$

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2 years ago

The prior probabilities for events A1 and A2 are P(A1) = 0.35 and P(A2) = 0.50. It is also known that P(A1 ∩ A2) = 0. Suppose P(

forsale [732]

Answer:

Step-by-step explanation:

Hello!

Given the probabilities:

P(A₁)= 0.35

P(A₂)= 0.50

P(A₁∩A₂)= 0

P(BIA₁)= 0.20

P(BIA₂)= 0.05

Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)

Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.

Considering that $P(BIA)= \frac{P(AnB)}{P(A)}$ you can clear the intersection from the formula $P(AnB)= P(B/A)*P(A)$ and apply it for the given events: