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Alex_Xolod [135]
3 years ago
12

A line passes through the points one, four and three, -4 which is the equation of the line

Mathematics
1 answer:
gavmur [86]3 years ago
6 0

ANSWER

y =  - 4x + 8

EXPLANATION

The given line passes through (1,4) and (3,-4).

The slope of this line is calculated using the formula:

m =\frac{y_2-y_1}{x_2-x_1}

We substitute the points into the slope formula to get:

m =  \frac{ - 4 - 4}{3 - 1}

\implies \: m =  \frac{ - 8}{2}

m =  - 4

We substitute the first point and slope into the point-slope formula

y-y_1=m(x-x_1)

This implies that

y -  4 =  - 4(x - 1)

We expand to get

y - 4 =  - 4x  +  4

y =  - 4x + 2/4+ 4

y =  - 4x + 8

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Step-by-step explanation:

We have given,

A rational function : f(x) = \frac{x-2}{x-4}

W need to find :

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For no values of x, we get indetermined form (i.e \frac{0}{0}), Hence there is no holes

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Plug y=f(x) = ∞ in f(x) to get vertical asymptote   {We can us writing ∞ = \frac{1}{0}}

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or \frac{1}{0}=\frac{x-2}{x-4}

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X -intercept :

Plug f(x)=0 , to get x intercept.

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or x - 2 =0

or x = 2

Hence at x=2, f(x) has an x intercept

Horizontal asymptote:

Plug x = ∞ in f(x) to get horizontal asymptote.

i.e f(x) = \frac{x-2}{x-4} = \frac{x(1-\frac{2}{x} )}{x(1-\frac{4}{x} )}

or f(x) = \frac{(1-\frac{2}{∞} )}{(1-\frac{4}{∞} )}

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6 0
3 years ago
What is the missing leg length of the hypotenuse 23 and the other leg is 11??
valentinak56 [21]
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The answer can be any of those.
6 0
2 years ago
Read 2 more answers
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