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4 years ago

A line passes through the points one, four and three, -4 which is the equation of the line

Mathematics

1 answer:

gavmur [86]4 years ago

6 0

ANSWER

$y = - 4x + 8$

EXPLANATION

The given line passes through (1,4) and (3,-4).

The slope of this line is calculated using the formula:

$m =\frac{y_2-y_1}{x_2-x_1}$

We substitute the points into the slope formula to get:

$m = \frac{ - 4 - 4}{3 - 1}$

$\implies \: m = \frac{ - 8}{2}$

$m = - 4$

We substitute the first point and slope into the point-slope formula

$y-y_1=m(x-x_1)$

This implies that

$y - 4 = - 4(x - 1)$

We expand to get

$y - 4 = - 4x + 4$

$y = - 4x + 2/4+ 4$

$y = - 4x + 8$

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2 years ago

Write the equation of the line that is perpendicular to x+y=-5 and passes through the point (7,3)

Anestetic [448]

Answer:

x - y = 4

Step-by-step explanation:

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Given

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y = - x - 5 ← in slope- intercept form

with slope m = - 1

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-1}$ = 1 , thus

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To find c substitute (7, 3) into the partial equation

3 = 7 + c ⇒ c = 3 - 7 = - 4

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