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jek_recluse [69]
2 years ago
6

(1) Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy so

urce is to store antimatter charged particles in a vacuum chamber, circulating in a magnetic field, and then extract them as needed. Antimatter annihilates with normal matter, producing pure energy. What strength magnetic field is needed to hold antiprotons, moving at 5.0 x 10^7 m/s in a circular path 2.00 m in radius? Antiprotons have the same mass as protons but the opposite (negative) charge.
(2) Is this field strength obtainable with today’s technology or is it a futuristic possibility?
Physics
1 answer:
malfutka [58]2 years ago
7 0

Solution :

The relationship between the strength of magnetic field and the radiusof a charged particle's path is obtained through Newton's second law, which is given by :

F = ma

F = qvB and $a=\frac{v^2}{r}$

Substituting these values in the second law of Newton,

$qvB=\frac{mv^2}{r}$

Now solving for B, we get:

$B = \frac{mv}{rq}$

  $=\frac{(1.67 \times 10^{-27})(5 \times 10^{7})}{2\times 1.6 \times 10^{-19}}$

 = 0.261 T

The field strength can be obtained by using the technology of today.

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ikadub [295]

Answer:

p_t_o_t_a_l=250kg\frac{m}{s}

Explanation:

<u>The total momentum of a system is defined by:</u>

(mv)_t_o_t=m_1v_1+m_2v_2+...

Where,

(mv)_t_o_t is the total momentum or it could be expressed also as p_t_o_t_a_l.

m_1 and m_2 represents the masses of the objects interacting in the system.

v_1 and v_2 are the velocities of the objects of the system.

<em>Remember: </em><em>The momentum is a fundamental physical magnitude of vector type.</em>

We have:

m_1=725 kg

v_1=15\frac{m}{s}\\m_2=625 kg

We are going to take the east side as positive, and the west side as negative. Then the velocity of the car B, has to be <u>negative</u>. It goes in a different direction from car A.

v_2=-17\frac{m}{s}

Then the total momentum of the system is:

p_t_o_t_a_l=m_1v_1+m_2v_2\\p_t_o_t_a_l=(725kg)(15\frac{m}{s})+(625kg)(-17\frac{m}{s})\\p_t_o_t_a_l=10875kg\frac{m}{s}-10625kg\frac{m}{s}\\p_t_o_t_a_l=250kg\frac{m}{s}

8 0
3 years ago
What would the weight of an astronaut be on Saturn if his mass is 68 kg and acceleration of gravity on Saturn is 10.44 m/s2? Ple
alex41 [277]

Here's the part you need to know:

       (Weight of anything) =

                 (the thing's mass)
times
                 (acceleration of gravity in the place where the thing is) .

                 Weight = (mass ) x (gravity) .

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You should memorize it.

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                   Weight = (mass ) x (gravity) .

                
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On Earth, gravity is only  9.8 m/s².
So as long as the astronaut is on Earth, his weight is only

                                   (68 kg) x (9.8 m/s²)

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Answer:

a. one line down one line to the right one live to the northwest from the object

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To make something electrical you need electricity and the wires will turn a magnet into an electromagnet.
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