From Doppler shifts of the spectral lines in the light coming from the east and west edges of the Sun, astronomers find that the
1 answer:
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Answer:
The rate of heat conduction through the layer of still air is 517.4 W
Explanation:
Given:
Thickness of the still air layer (L) = 1 mm
Area of the still air = 1 m
Temperature of the still air ( T) = 20°C
Thermal conductivity of still air (K) at 20°C = 25.87mW/mK
Rate of heat conduction (Q) = ?
To determine the rate of heat conduction through the still air, we apply the formula below.
Q = 517.4 W
Therefore, the rate of heat conduction through the layer of still air is 517.4 W
Answer:
c. 0.816
Explanation:
Let the mass of car be 'm' and coefficient of static friction be 'μ'.
Given:
Speed of the car (v) = 40.0 m/s
Radius of the curve (R) = 200 m
As the car is making a circular turn, the force acting on it is centripetal force which is given as:
Centripetal force is,
The frictional force is given as:
Friction = Normal force × Coefficient of static friction
As there is no vertical motion, therefore, . So,
Now, the centripetal force is provided by the frictional force. Therefore,
Frictional force = Centripetal force
Plug in the given values and solve for 'μ'. This gives,
Therefore, option (c) is correct.