Ask question

Ask question

All categories

tankabanditka [31]

3 years ago

5

The liquid mercury in a thermometer expands as it is heated. this is a...

2 answers:

Juliette [100K]3 years ago

8 0

THE ANSWER IS

physical change.

dedylja [7]3 years ago

5 0

Change of State and a Physical Change

You might be interested in

What does it mean when work is positive?

dmitriy555 [2]

Answer:

When force and displacement are in the same direction, the work performed on an object is said to be positive work. Example: When a body moves on the horizontal surface, force and displacement act in the forward path. The work is done in this case known as Positive work.

Explanation:

Hope this helps you

5 0

3 years ago

Read 2 more answers

An 888.0 kg elevator is moving downward with a velocity of 0.800 m/s. It decelerates uniformly and comes to a stop in a distance

bagirrra123 [75]

Answer:

The value of tension on the cable T = 1065.6 N

Explanation:

Mass = 888 kg

Initial velocity ( u )= 0.8 $\frac{m}{sec}$

Final velocity ( V ) = 0

Distance traveled before come to rest = 0.2667 m

Now use third law of motion $V^{2}$ = $u^{2}$ - 2 a s

Put all the values in above formula we get,

⇒ 0 = $0.8^{2}$ - 2 × a ×0.2667

⇒ a = 1.2 $\frac{m}{sec^{2} }$

This is the deceleration of the box.

Tension in the cable is given by T = F = m × a

Put all the values in above formula we get,

T = 888 × 1.2

T = 1065.6 N

This is the value of tension on the cable.

5 0

3 years ago

A figure shows a vertically moving block on the end of a cord. The graph next to the figure gives the vertical velocity componen

Sergio [31]

It should be 2/9/10 in functional form

3 0

3 years ago

What is the mass of a rock lifted 2 meters off the ground that has 196 J of potential energy?

eimsori [14]

Answer:

10kg

Explanation:

Let PE=potential energy

PE=196J

g(gravitational force)=9.8m/s^2

h(change in height)=2m

m=?

PE=m*g*(change in h)

196=m*9.8*2

m=10kg

4 0

3 years ago

ly charged particles are held 24 x 103m apart and then released from rest. The initial acceleration of the first particle is obs

inessss [21]

Answer:

Part a)

$m_2 = 4.9 \times 10^7 kg$

Part b)

$q_1 = q_2 = 5312.6 C$

Explanation:

Part a)

As we know that both charge particles will exert equal and opposite force on each other

so here the force on both the charges will be equal in magnitude

so we will have

$F = m_1a_1 = m_2a_2$

here we have

$6.3 \times 10^7(7) = m_2(9)$

now we have

$m_2 = 4.9 \times 10^7 kg$

Part b)

Now for the force between two charges we can say

$F = \frac{kq_1q_2}{r^2}$

now we have

$(6.3 \times 10^7)(7) = \frac{(9\times 10^9)q^2}{(24\times 10^3)^2}$

now we have

$q_1 = q_2 = 5312.6 C$

3 0

3 years ago