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Crank
3 years ago
10

A soccer ball is kicked from the ground with a velocity of 30m/s directed at an angle of 45 degrees with respect to horizontal.

Resolve this velocity vector into horizontal and Vertical components
Physics
1 answer:
Alinara [238K]3 years ago
5 0

Answer:

Vertical = 21.2 m/s

Horizontal = 21.2 m/s

Explanation:

For the vertical component:

sin (45) = v/30

sin (45) x 30 = v

21.2 m/s = v

For the horizontal component:

cos (45) = h/30

cos (45) x 30 = h

21.2 m/s = h

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A geneticist looks through a microscope to determine the phenotype of a fruit fly. The microscope is set to an overall magnifica
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Answer:

f_{e}  = 1.9 cm

Explanation:

The magnification of a microscope is the product of the magnification of the eyepiece by the magnifier with the objective

    M = M₀ m_{e}

Where M₀ is the magnification of the objective and  m_{e} is the magnification of the eyepiece.

The eyepiece is focused to the near vision point (d = 25 cm)

       m_{e} = 25 /  f_{e}

The objective is focused on the distances of the tube (L)

     M₀ = -L / f₀

Substituting

     M = - L/f₀    25/f_{e}  

1) Let's look for the focal length of the eyepiece (faith)

     f_{e}  = - L 25 / f₀ M

     M = 400X = -400

     f_{e}  = - 12 25 /0.40 (-400)

     f_{e}  = 1.875 cm

Let's approximate two significant figures

    f_{e}  = 1.9 cm

8 0
3 years ago
Use 3rd law to explain how a fish swims through water. Identify the force pairs and draw a diagram.
vovikov84 [41]
Well as the fish swims he pushes the water behind him which in return push him forward
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An energy storage system based on a flywheel (a rotating disk) can store a maximum of 3.7 MJ when the flywheel is rotating at 16
Likurg_2 [28]

The moment of inertia of the flywheel is 2.63 kg-m^{2}

It is given that,

The maximum energy stored on the flywheel is given as

E=3.7MJ= 3.7×10^{6} J

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So to find the moment of inertia of the flywheel. The energy of a flywheel in rotational kinematics is given by :

E = \frac{1}{2}Iw^{2}

By rearranging the equation:

I = \frac{2E}{w_{2} }

I = 2.63 kg-m^{2}

Thus the moment of inertia of the flywheel is 2.63 kg-m^{2}.

Learn more about moment of inertia here;

brainly.com/question/13449336

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7 0
1 year ago
A trunk rotation is a common dyamic flexibility assessment ture or false
Ilia_Sergeevich [38]

True. It would be false if the statement was "trunk rotation is the most common <em>static</em> flexibility assessment."


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6 0
3 years ago
A Neglecting air resistance, a ball projected straight upward so it remains in the air for 10 seconds needs an initial speed of
ololo11 [35]

Answer:

The initial velocity is 50 m/s.

(C) is correct option.

Explanation:

Given that,

Time = 10 sec

For first half,

We need to calculate the height

Using equation of motion

v^2=u^2+2gh

h =\dfrac{v^2}{2g}....(I)

For second half,

We need to calculate the time

Using equation of motion

h =ut+\dfrac{1}{2}gt_{2}^2

h=0+\dfrac{1}{2}gt_{2}^2

t_{2}=\sqrt{\dfrac{2h}{g}}

Put the value of h from equation (I)

t_{2}=\sqrt{\dfrac{2\times v^2}{g^2}}

t_{2}=\dfrac{v}{g}

According to question,

t_{1}+t_{2}=10

t_{1}=t_{2}

Put the value of t₁ and t₂

\dfrac{v}{g}+\dfrac{v}{g}=10

\dfrac{2v}{g}=10

v=\dfrac{10\times g}{2}

Here, g = 10

The initial velocity is

v=\dfrac{10\times10}{2}

v=50\ m/s

Hence, The initial velocity is 50 m/s.

3 0
3 years ago
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