Answer:
#1: No #2: Yes #3: Yes #4: Yes
Answer
Find out the number of hours when the cost of parking at both garages will be the same.
To prove
As given
There are two parking garages in beacon falls .
As given
Let us assume that the y is representing the cost of parking at both garages will be the same.
The total number of hours is represented by the x.
First case
Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .
As garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)
Than the equation becomes
y = 3.00 (x -2) + 7.00
written in the simple form
y = 3x - 6 +7
y = 3x + 1
Second case
Garage b charges $3.25 per hour to park.
than the equation becomes
y = 3.25x
Compare both the equations
3x +1 = 3.25x
3.25x -3x = 1
.25x = 1

x = 4hours
Therefore in the 4 hours the cost of parking at both garages will be the same.
Answer:
You wrote the question wrong...
m is not -16 it is -1/6 (that is a big difference)
y=mx+b
y=-1/6x+b
3 = -1/6(12) + b
3 = -2 + b
b=5
Step-by-step explanation:
Answer:
8cm
Step-by-step explanation:
First you must know that the diameter of the semi-circular patio is equal to the length of one side of the square
Area of a semi circle = πr²/2
25.12 = πr²
25.12 = 3.14r²/2
r² = 25.12(2)/3.14
r² = 16
r = √16
r = 4
Get the diameter
d = 2r
d =2(4)
d = 8cm
Hence the length of the side of the square is 8cm
X + x + 24 = 58
x = (58-24)/2=17
the first number is 17 and the second number is the sum of 17 and 28. Finding it has been left as an exercise for the reader.