What is the approximate mass of a 100-N person on Earth? Question options: 1 kg 10 kg 100 kg 1,000 kg

How many moles are represented by 3.01 - 1023 helium atoms?

Pavlova-9 [17]

Answer:

0.5 mol

Explanation:

Given data:

Number of atoms of He = 3.01 ×10²³

Number of moles = ?

Solution:

Avogadro number:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.02 × 10²³ is called Avogadro number.

1 mole = 6.02 × 10²³ atoms

3.01 ×10²³ atoms × 1 mol / 6.02 × 10²³ atoms

0.5 mol

7 0

3 years ago

HELPPPPPPP PLZZZ

Ganezh [65]

Answer:

The potential energy the apple had due to its height is converted to kinetic energy

Explanation:

When an apple falls from the tree to the ground, its <u>energy of position stored as gravitational potential energy is converted to kinetic energy</u>, the energy of motion, as it falls. When the apple hits the ground, kinetic energy is transformed into heat energy.

7 0

3 years ago

what would be the observation when you dipp magnesium hydroxide in a blue litmus paper and a red litmus paper. also what would b

Ludmilka [50]

Answer:

red litmus will turn blue

blue litmus will remain blue

Explanation:

magnesium hydroxide is a base therefore turns red litmus paper blue

4 0

3 years ago

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"Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it

Alex17521 [72]

Answer:

$\boxed{\text{0.50 mol/L}}$

Explanation:

The balanced equation is

2COF₂ ⇌ CO₂+CF₄; Kc = 9.00

1. Set up an ICE table

$\begin{array}{ccccc}\rm 2COF_{2} & \, \rightleftharpoons \, & \rm CO_{2} & +&\rm CF_{4}\\2.00& & 0& & 0\\-x& & +x & & +x\\2.00 - x& & x & &x \\\end{array}$

2. Solve for x

$K_{c} = \dfrac{[\rm CO][ \rm CF_{4}]}{[\rm COF_{2}]^{2}} = 9.00\\\\\begin{array}{rcl}\dfrac{x^{2}}{(2.00 - x)^{2}} & = & 9.00\\\dfrac{x}{2.00 - x} & = & 3.00\\x & = &3.00(2.00 - x)\\x & = & 6.00 - 3.00x\\4.00x & = & 6.00\\x & = & \mathbf{1.50}\\\end{array}$