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vekshin1
3 years ago
11

How do you know if you have a balanced equation?

Chemistry
1 answer:
Charra [1.4K]3 years ago
3 0
If each side of the equation has the same number of atoms of a given element, that element is balanced.
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When 70.4 g of benzamide (C7H7NO) are dissolved in 850. g of a certain mystery liquid X , the freezing point of the solution is
lora16 [44]

Answer:

i=1.62 .

Explanation:

Let, i be the Van't Hoff Factor.

Moles of benzamide,=\dfrac{Mass}{molar\ mass}=\dfrac{70.4}{121.14}=0.58\ mol.

Molality of solution, m=\dfrac{moles  }{mass\ of\ solvent}=\dfrac{0.58}{0.85}=0.68\ molal.

Now, we know

Depression in freezing point, \Delta T=i\times K_f\times m  .....1

It is given that,

\Delta T=2.7^o C\\i=1 ( since\ it\ is\ non\ dissociable\ solutes)\\K_f  ( freezing\ constant)\\

Putting all these values we get,

K_f=3.949\ C/m.

Now, moles of ammonium chloride=\dfrac{70.4}{53.49}=1.316\ mol.

molality =\dfrac{1.316}{0.85}=1.54 molal.\\\Delta T=9.9 .

Putting all these values in eqn 1.

We get,

i=1.62 .

Hence, this is the required solution.

6 0
3 years ago
Calculate the density of an<br> object with a mass of 58g and a<br> volume of 20 mL.<br> Enter
Sveta_85 [38]

Answer:

D = 2.9 g/mL

Explanation:

Density = Mass over Volume

D = m/V

Step 1: Define

m = 58 g

V = 20 mL

D = unknown

Step 2: Substitute and Evaluate for Density

D = 58 g/20 mL

D = 2.9 g/mL

7 0
3 years ago
What is the correct charge for an ion of K
weeeeeb [17]

Answer:

1+

Explanation:

Potassium ion has a charge of 1+

4 0
3 years ago
HELP I HAVE TO SUBMIT IN 5 MINS!!!!!!! :( I HAVE NO IDEA!!!
lawyer [7]
742 - 21.1 = 720.9 torr
7 0
3 years ago
What do the observations for changes to volume and pressure show you about the
Irina-Kira [14]

Answer: The given demonstration does not support Boyle's Law.

Explanation:

According to Boyle's law, at constant temperature the pressure of an ideal gas is inversely proportional to the volume of gas.

P \propto \frac{1}{V}

Therefore, an increase in volume of gas will lead to a decrease in pressure and vice-versa.

Now, according to the given data of volumes there is occurring an increase on moving from final volume 1 to final volume 3. This means that pressure is decreasing.

As a result, if a balloon was squeezed or compressed then it would get smaller. But in the given demonstration pressure is not given.

Thus, we can conclude that the given demonstration does not support Boyle's Law.

3 0
3 years ago
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