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xxTIMURxx [149]
3 years ago
9

Complete the following paragraph to describe how the electrostatic forces in salt compounds can be overcome by interactions betw

een the solvent molecules and the salt compounds. Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.
(1) insoluble
(2) ionic bonds
(3) ion-dipole forces
(4) soluble
(5) hydrogen bonds
(6) dipole-dipole forces
(7) covalent bonds
(8) higher
(9) dispersion forces
(10) lower

Salts are composed of ions that form a tightly packed and ordered network, which is called a crystal lattice, and it is held together by ____.
When a salt is added to a polar solvent like water, the ions interact with the solvent molecules via ____, which overcome the forces originally holding the ions together.
The ions are then isolated and stabilized in solution via these interactions, and when this occurs for most of the salt compound, it is considered in ____ that solvent.
Due to the nature of the interaction between ions and solvent molecules, a concentration of ions can be dissolved ____in water than in alcohol.
Chemistry
1 answer:
motikmotik3 years ago
3 0

Answer:

The words are: (2) ionic bonds; (3) ion-dipole forces; (4) soluble; (8) higher

Explanation:

-Salts are composed of ions that form a tightly packed and ordered network, which is called a crystal lattice, and it is held together by <u>ionic bonds</u>.

<u><em>Explanation</em></u><em>: salts are ionic compounds, which are composed by oppositely charged ions (cations and anions) which are bonded each other by ionic bonds, in an ordered arrangement, often a crystalline solid.</em>

-When a salt is added to a polar solvent like water, the ions interact with the solvent molecules via <u>ion-dipole forces</u>, which overcome the forces originally holding the ions together.

<em>Explanation: the molecules of a polar solvent are dipoles because they have dipolar momentum (a difference in charge due to a electronegativiy difference). When a salt is dissolved in a polar solvent, it dissociates in ions. So, the resulting interactions between these species are ion-dipole forces.</em>

-The ions are then isolated and stabilized in solution via these interactions, and when this occurs for most of the salt compound, it is considered <u>soluble</u> in that solvent.

<em>Explanation: the ions in solution are surrounded by solvent molecules which stabilizes them. A salt which is enterely dissolved in a solvent is soluble in that solvent.</em>

-Due to the nature of the interaction between ions and solvent molecules, a concentration of ions can be dissolved <u>higher</u> in water than in alcohol.

<em>Explanation: water molecules have unique properties that make water an universal solvent. Due to these properties and its polarity, water can dissolve larger quantities of salt than other polar solvents such as alcohol. </em>

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A particular reactant decomposes with a half‑life of 113 s when its initial concentration is 0.331 M. The same reactant decompos
algol13

Answer:

The reaction is second-order, and k = 0.0267 L mol^-1 s^-1

Explanation:

<u>Step 1:</u> Data given

The initial concentration is 0.331 M

half‑life time =  113 s

The same reactant decomposes with a half‑life of 243 s when its initial concentration is 0.154 M.

<u>Step 2: </u>Determine the order

The reaction is not first-order because the half-life of a first-order reaction is independent of the initial concentration:

t½ = (ln(2))/k

Calculate k for the two conditions given:

⇒ 113 s with initial concentration is 0.331 M

t½ = ([A]0)/2k

113 s = (0.331 M)/2k

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⇒ 243 s with an initial concentration is 0.154 M

t½ = ([A]0)/2k

243 s = (0.154 M)/2k

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The <u>values of k are different</u>, so that rules out zero-order.

<u>Step 3: </u>Calculate if it's a second-order reaction

For a second-order reaction, the half-life is given by the expression

t½ = 1/((k*)[A]0))

<u>Calculate k for the two conditions given: </u>

⇒ 113 s when its initial concentration is 0.331 M

t½ = 1/((k*)[A]0))

113 s = 1/(k*(0.331 M))

k = 1/((0.331 M)*(113 s)) = 0.0267 L mol^-1 s^-1

⇒ 243 s when its initial concentration is 0.154 M

t½ = 1/((k*)[A]0))

243 s = 1/(k*(0.154 M))

k = 1/((0.154 M)*(243 s)) =  0.0267 L mol^-1 s^-1

The values of k are the same, so the reaction is second-order, and k = 0.0267 L mol^-1 s^-1

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Answer:

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Explanation:

Number of moles trichloroethylene = pressure × volume/Henry's constant = 0.00301×0.21/0.00985 = 0.0642 mol

Volume of mixture = 100 L

Concentration of trichloroethylene = number of moles of trichloroethylene/volume of solution = 0.0642/100 = 6.42×10^-4 M

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Answer:

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Hope this helps:D
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