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Anna [14]
2 years ago
11

Find the product of √4(√8+3)

Mathematics
2 answers:
kotykmax [81]2 years ago
7 0

Answer:

6+4\sqrt{2}

Step-by-step explanation:

\sqrt{4} (\sqrt{8} +3)

2(\sqrt{8} +3)

2(\sqrt{8} )+2(3)

2\sqrt{8}  +6

2 \times 2\sqrt{2} +6

4\sqrt{2} +6

Scrat [10]2 years ago
3 0

Answer:

2(2.82 + 3)

2(5.82)

11.65

Step-by-step explanation:

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What is the area of a circle with a diameter of 12.6 in.?
Zepler [3.9K]

Hey there! I'm happy to help!

To find the area of a circle, you square the radius and then multiply by pi (3.14 in our case).

The radius is half of the diameter.

12.6/2=6.3

We square this.

6.3²=39.69

We multiply by 3.14

39.69×3.14=124.6266

We round to the nearest hundredth, giving us an area of 124.63 in².

Now you can find the area of a circle! Have a wonderful day! :D

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What is the slope of the line that passes through the pair of points (3,-4) and (5,-7).
maria [59]

The correct answer is C. -3/2

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3 years ago
I need the answer for this exact question
denis23 [38]

Answer:

y=\frac{7}{2}x-20

Step-by-step explanation:

Let the equation of the line be y-y_1=m(x-x_1) where, 'm' is its slope and (x_1,y_1) is a point on it.

Given:

The equation of a known line is:

y=-\frac{2}{7}x+9

A point on the unknown line is:

(x_1,y_1)=(4,-6)

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is m_1=-\frac{2}{7}

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20

The equation of a line perpendicular to the given line and passing through (4, -6) is y=\frac{7}{2}x-20.

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