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Vikki [24]
3 years ago
10

A large but sparsely populated county has two small hospitals, one at the south end of the county and the other at the north end

. The south hospital’s emergency room has four beds, whereas the north hospital’s emergency room has only three beds. Let X denote the number of south beds occupied at a particular time on a given day, and let Y denote the number of north beds occupied at the same time on the same day. Suppose that these two rv’s are independent; that the pmf of X puts probability masses .1, .2, .3, .2, and .2 on the x values 0, 1, 2, 3, and 4, respectively; and that the pmf of Y distributes probabilities .1, .3, .4, and .2 on the y values 0, 1, 2, and 3, respectively.a. Display the joint pmf of X and Y in a joint probability table.b. Compute P(X # 1 and Y # 1) by adding probabilities from the joint pmf, and verify that this equals the product of P(X # 1) and P(Y # 1).c. Express the event that the total number of beds occupied at the two hospitals combined is at most 1 in terms of X and Y, and then calculate this probability.d. What is the probability that at least one of the two hospitals has no beds occupied?Devore, Jay L.. Probability and Statistics for Engineering and the Sciences (Page 210). Brooks Cole. Kindle Edition.

Mathematics
1 answer:
mihalych1998 [28]3 years ago
3 0

Answer:

a) The table is in the attached file

b) P(X=1, Y =1) = P(X=1)P(Y=1)

c) 0.06

d) 0.19

Step-by-step explanation:

Check the attached files for the solutions and explanations for questions a to d

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Answer:

Therefore 200.96 ft.of fencing are needed to go around the pool path.

Step-by-step explanation:

Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.

The radius of the outside edge the pool path is

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= (28+4) ft

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To find the length of fencing, we need to find the circumference of outside the pool path.

Here r= 32 ft

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Answer:

Step-by-step explanation:

Area = length * width

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1. First numbers: multiply the first number of each binomial together--x*x = x%5E2

2. Outer numbers: multiply the outer number of each binomial (out of the entire expression, the number farthest to the left (x) and the number farthest to the right (-5))--x*-5 = -5x

3. Inner numbers: multiply the inner number of each binomial--3*x = 3x

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Answer:

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Step-by-step explanation:

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