Answer:
Therefore 200.96 ft.of fencing are needed to go around the pool path.
Step-by-step explanation:
Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.
The radius of the outside edge the pool path is
= Radius of the pool + The width of the path
= (28+4) ft
= 32 ft.
To find the length of fencing, we need to find the circumference of outside the pool path.
Here r= 32 ft
The circumference of outside edge of the pool path
=

=200.96 ft.
Therefore 200.96 ft.of fencing are needed to go around the pool path.
Answer:
Step-by-step explanation:
Area = length * width
length: x + 3
width: x - 5
A = (x + 3)(x - 5)
Simplify (x + 3)(x - 5) using the FOIL method:
1. First numbers: multiply the first number of each binomial together--x*x = x%5E2
2. Outer numbers: multiply the outer number of each binomial (out of the entire expression, the number farthest to the left (x) and the number farthest to the right (-5))--x*-5 = -5x
3. Inner numbers: multiply the inner number of each binomial--3*x = 3x
4. Last numbers: multiply the last number of each binomial--3*-5 = -15
==> Now, add all of the results together and combine like terms: x%5E2+-+5x+%2B+3x+-+15 = x%5E2+-+2x+-+15
Therefore, A = x%5E2+-+2x+-+15
Answer:
8
Step-by-step explanation:
The domain is from the points (-4,0) through (4,0).
Answer:
the answer is V≈2144.66
Step-by-step explanation:
give me brainliest
<span>x ≥ -80/3 is the answer
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