<u>Answer:</u> The number of moles of HI in the solution is 
moles.
<u>Explanation:</u>
We are given:
To calculate the concentration of a substance, we use the equation:
......(1)
- Concentration of ammonia:
![[NH_3]=\frac{0.405mol}{4.90L}=0.083mol/L](https://tex.z-dn.net/?f=%5BNH_3%5D%3D%5Cfrac%7B0.405mol%7D%7B4.90L%7D%3D0.083mol%2FL)
- Concentration of ammonium iodide:
![[NH_4I]=\frac{1.45mol}{4.90L}=0.30mol/L](https://tex.z-dn.net/?f=%5BNH_4I%5D%3D%5Cfrac%7B1.45mol%7D%7B4.90L%7D%3D0.30mol%2FL)
For the given chemical reaction:
The expression of 
for above equation follows:
![K_c=\frac{[HI][NH_3]}{[NH_4I]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BHI%5D%5BNH_3%5D%7D%7B%5BNH_4I%5D%7D)
Putting values in above equation, we get:
![7.0\times 10^{-5}=\frac{[HI]\times 0.083}{0.30}](https://tex.z-dn.net/?f=7.0%5Ctimes%2010%5E%7B-5%7D%3D%5Cfrac%7B%5BHI%5D%5Ctimes%200.083%7D%7B0.30%7D)
![[HI]=2.53\times 10^{-4}](https://tex.z-dn.net/?f=%5BHI%5D%3D2.53%5Ctimes%2010%5E%7B-4%7D)
Calculating the moles of hydrogen iodide by using equation 1, we get:
Hence, the number of moles of HI in the solution is moles.
Explanation:
Magnesium chloride = MgCl₂
aluminum nitrate= Al(NO₃)₃
ammonium sulfate=( NH₄)₂SO₄
They seem to eat a lot ranging from woody plants to vines, though in the rainforest most of their diet is made up of Malaysia and plant material, to be more specific
So I would go with leaves, 50%
Flowers, buds, and insects, 10%
Fruits, 40%
--They also really like figs
Answer:
burning of wood ,cooking an egg,baking a cake,rusting of iron,digestion of food .
Delta E = Ef - Ei
E = energy , h = plank constant , v = frequency
h= 6.626 * 10 ^-34 j*s , T = 10 ^ 12 , v = 74 * 10 ^12 Hz , Hz = s^-1
E = ( 6.626 * 10^ -34 j*s) ( 74 * 10 ^ 12 s^ -1 ) = 4.90 * 10 ^ -20 J
Delta E = Ef - Ei
-4.90 * 10 ^ -20 J = -2.18 * 10 ^ -18J ( 1/4 ^2 - 1/x ^2)
0.0225 = 0.0625 - ( 1/x ^ 2)
0.225 - 0.0625 = - 1/ x ^ 2
- 0.0400 = - 1/x ^2 = -1 / - 0.0400 = x^2
25 = x^2
x = 5
