It is approximately 0. It could be barley higher or lower for both. You have to take the altitude into consideration.
Answer:
3.937 x 10⁻⁸ inches
Explanation:
Data Given:
Atomic radium in pm (picometer) = 1.00 x 10² pm
Atomic radium in inches = ?
1 pm = 10⁻¹² m
Solution:
First convert picometer to meter
As we Know
1 pm = 10⁻¹² m
then
1.00 x 10² pm = X meter
Do cross multiplication
X meter = (1.00 x 10² pm)(10⁻¹² m) / 1 pm
X meter = 1 x 10⁻⁹ m
So, 1.00 x 10² pm equal to 1 x 10⁻⁹ m
Now convert meter to inches
As
1 m = 39.37 inches
1 x 10⁻⁹ m = X inches
Do cross multiplication
X inches = (39.3701 inches)(1 x 10⁻⁹ m ) / 1 m
X inches = 3.937 x 10⁻⁸ inches
So,
1.00 x 10² pm = 3.937 x 10⁻⁸ inches
so the radius is 3.937 x 10⁻⁸ inches
Mass / volume = density
2.72g/0.121mL = 22.5g/mL
1cm3 = 1mL
Answer:
2H₂O₂ → 2H₂O + O₂
Explanation:
H₂O₂ → H₂O + O₂
The above equation can be balance as illustrated below:
H₂O₂ → H₂O + O₂
There are 2 atoms of O on the left side and a total of 3 atoms on the right side. It can be balance by putting 2 in front of H₂O₂ and 2 in front of H₂O as shown below:
2H₂O₂ → 2H₂O + O₂
Now, the equation is balanced.
**** check ****
Element >>> Left Side >>> Right Side
H >>>>>>>>> 4 >>>>>>>>> 4
O >>>>>>>>> 4 >>>>>>>>> 4
Answer:
17.76g
Explanation:
We need to write a balanced chemical equation for the reaction:
2Al(OH)3 + 3Ca(NO3)2 ——> 3Ca(OH)2 + 2Al(NO3)3
In the reaction above, it can be seen that 2 moles of aluminum hydroxide yielded 3 moles of calcium hydroxide. This is the theoretical viewpoint.
Now we need to know what actually happened. We need to calculate the actual number of moles of aluminum hydroxide reacted l. We can get this by dividing the mass by the molar mass.
The molar mass of aluminum hydroxide is 27+ 3( 16+1)
= 27 + 51 = 78g/mol
The number of moles is thus: 12.55/78 = 0.16 moles
Now if 2 moles of aluminum hydroxide gave 3 moles of calcium hydroxide, 0.16moles will give : (0.16*3)/2 = 0.24moles
Now we can calculate the mass of calcium hydroxide formed. The mass of calcium hydroxide formed is the number of moles multiplied by the molar mass.
The molar mass of calcium hydroxide is; 40 + 2(17) = 74g/mol
The mass is thus =74 * 0.24 = 17.76g
