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PolarNik [594]
2 years ago
6

HELP ME PLEASE. Which of the following statements is true for electrolysis? New atoms are created by destroying old atoms. A com

pound is heated to form multiple products. An electric current is used to synthesize a substance. An electric current is used to decompose a substance.
Chemistry
1 answer:
babymother [125]2 years ago
5 0
<h3>Answer:</h3>

An electric current is used to decompose a substance.

<h3>Explanation:</h3>

Concept tested: Electrolysis

We can answer the question by asking ourselves important questions

First; What is electrolysis?

  • Electrolysis refers to the process through which molten or aqueous compound known as electrolytes are decomposed by passing electric current through them.

Second; What are electrolytes?

  • Electrolytes are substances in either molten or aqueous form and are good conductors of electric current.
  • Electrolytes are good conductors of electric current due to the presence of mobile ions.

Third: What happens during electrolysis?

  • Electrolytes are therefore decomposed by passing electric current through them resulting to formation of new elements or molecules.
  • For example, when molten sodium chloride is decomposed by passing electric current through it, sodium metal is released at the cathode while chlorine is released at the anode.
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The dissociation of sulfurous acid (H2SO3) in aqueous solution occurs as follows:
aksik [14]

Answer:

The [SO₃²⁻]

Explanation:

From the first dissociation of sulfurous acid we have:

                         H₂SO₃(aq) ⇄ H⁺(aq) + HSO₃⁻(aq)

At equilibrium:  0.50M - x          x            x

The equilibrium constant (Ka₁) is:

K_{a1} = \frac{[H^{+}] [HSO_{3}^{-}]}{[H_{2}SO_{3}]} = \frac{x\cdot x}{0.5 - x} = \frac {x^{2}}{0.5 -x}

With Ka₁= 1.5x10⁻² and solving the quadratic equation, we get the following HSO₃⁻ and H⁺ concentrations:

[HSO_{3}^{-}] = [H^{+}] = 7.94 \cdot 10^{-2}M

Similarly, from the second dissociation of sulfurous acid we have:

                              HSO₃⁻(aq) ⇄ H⁺(aq) + SO₃²⁻(aq)

At equilibrium:  7.94x10⁻²M - x          x            x

The equilibrium constant (Ka₂) is:  

K_{a2} = \frac{[H^{+}] [SO_{3}^{2-}]}{[HSO_{3}^{-}]} = \frac{x^{2}}{7.94 \cdot 10^{-2} - x}  

Using Ka₂= 6.3x10⁻⁸ and solving the quadratic equation, we get the following SO₃⁻ and H⁺ concentrations:

[SO_{3}^{2-}] = [H^{+}] = 7.07 \cdot 10^{-5}M

Therefore, the final concentrations are:

[H₂SO₃] = 0.5M - 7.94x10⁻²M = 0.42M

[HSO₃⁻] = 7.94x10⁻²M - 7.07x10⁻⁵M = 7.93x10⁻²M

[SO₃²⁻] = 7.07x10⁻⁵M

[H⁺] = 7.94x10⁻²M + 7.07x10⁻⁵M = 7.95x10⁻²M

So, the lowest concentration at equilibrium is [SO₃²⁻] = 7.07x10⁻⁵M.

I hope it helps you!

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Is mixing salt and pepper physical change or chemical change ?
Rom4ik [11]
Yes mixing salt with pepper change
6 0
3 years ago
Extended networks of pi bonds can cause a delocalization of electrons. Explain how this occurs.
algol [13]
The answer is: Electrons are shared in each pi bond. If the pi bonds flip back and forth between the adjacent p-orbitals on the two sides of an atom, the shared electrons in the p-orbitals can become delocalized.



Hope this help
7 0
3 years ago
GUYS I NEED THIS ASAP ​
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It’s DEFINITELY 2 like DEFINITELY
8 0
2 years ago
Please help
Mashutka [201]

Answer:

Potential

Explanation:

The answer is potential!

6 0
1 year ago
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