Answer:
![2\,(x-1)^2=4](https://tex.z-dn.net/?f=2%5C%2C%28x-1%29%5E2%3D4)
which is the first option in the list of possible answers.
Step-by-step explanation:
Recall that the minimum of a parabola generated by a quadratic expression is at the vertex of the parabola, and the formula for the vertex of a quadratic of the general form:
![y=ax^2+bx+c](https://tex.z-dn.net/?f=y%3Dax%5E2%2Bbx%2Bc)
is at ![x_{vertex}=\frac{-b}{2\,a}](https://tex.z-dn.net/?f=x_%7Bvertex%7D%3D%5Cfrac%7B-b%7D%7B2%5C%2Ca%7D)
For our case, where
we have:
![x_{vertex}=\frac{-b}{2\,a}\\x_{vertex}=\frac{4}{2\,*\,2}\\x_{vertex}=1](https://tex.z-dn.net/?f=x_%7Bvertex%7D%3D%5Cfrac%7B-b%7D%7B2%5C%2Ca%7D%5C%5Cx_%7Bvertex%7D%3D%5Cfrac%7B4%7D%7B2%5C%2C%2A%5C%2C2%7D%5C%5Cx_%7Bvertex%7D%3D1)
And when x = 1, the value of "y" is:
![y(x)=2x^2-4x-2\\y(1)=2(1)^2-4(1)-2\\y(1)=2-6\\y(1)=-4\\y_{vertex}=-4](https://tex.z-dn.net/?f=y%28x%29%3D2x%5E2-4x-2%5C%5Cy%281%29%3D2%281%29%5E2-4%281%29-2%5C%5Cy%281%29%3D2-6%5C%5Cy%281%29%3D-4%5C%5Cy_%7Bvertex%7D%3D-4)
Recall now that we can write the quadratic in what is called: "vertex form" using the coordinates
of the vertex as follows:
![y-y_{vertex}=a\,(x-x_{vertex})^2](https://tex.z-dn.net/?f=y-y_%7Bvertex%7D%3Da%5C%2C%28x-x_%7Bvertex%7D%29%5E2)
Then, for our case:
![y-(-4)=2\,(x-1)^2\\y=2\,(x-1)^2-4](https://tex.z-dn.net/?f=y-%28-4%29%3D2%5C%2C%28x-1%29%5E2%5C%5Cy%3D2%5C%2C%28x-1%29%5E2-4)
Then, for the quadratic equal to zero as requested in the problem, we have:
![y=2\,(x-1)^2-4=0\\2\,(x-1)^2-4=0\\2\,(x-1)^2=4](https://tex.z-dn.net/?f=y%3D2%5C%2C%28x-1%29%5E2-4%3D0%5C%5C2%5C%2C%28x-1%29%5E2-4%3D0%5C%5C2%5C%2C%28x-1%29%5E2%3D4)
Answer:
yo need more photos
Step-by-step explanation:
The answer is 140 percent
Answer:
d
Step-by-step explanation:
Answer:
110 beats per minute.
Step-by-step explanation:
Since we know it beats 6600 beats per hour and there are 60 minutes in an hour then we have to divide 6600 by 60 which is 110.