Answer:
the circumference of the outer edge of the path around the pool is 113.04 ft
Step-by-step explanation:
Hello, I think I can help you with this
the circumference is given by:
S=2π*r
where, S is the length of the circumference,π=3.14159.., r= radius
Step one
define the radius
the total radius of the pool and the path is
radius=15 ft + 3 ft
radius=18 ft
Step two
π=3.14
radius=18 ft
put the values into the equation
S=2π*r
S=2*3.14*18 ft
S=113.04 ft
the circumference of the outer edge of the path around the pool is 113.04 ft
I hope it helps, Have a nice day.