Question

Can someone help please ? (4x+3)(2x-5)

Answer 1

We FOIL it, multiplying firsts, outers, inners, and lasts.

(4x+3)(2x-5)

= (4x)(2x) + (4x)(-5) + (3)(2x) + (3)(-5)

= 8x² - 20x + 6x - 15

= 8x² -14x - 15

Answer: 8x² -14x - 15

Answer 2

Answer:

$8x^{2}$ - 14x - 15

Step-by-step explanation:

(4x + 3) (2x - 5)

you multiply everything in the second parentheses by the first number in the first parentheses

write those numbers down

then multiply the number in the second parentheses again by the second factor in the first parentheses

(4x) (2x - 5)

4x · 2x = 8x²

8x²

4x · -5 = -20x

8x² - 20x

that's the first part of the equation

then, moving on

(3) (2x - 5)

3 · 2x = 6x

6x

3 · -5 = -15

6x - 15

then, put them together and you get

8x² - 20x + 6x - 15

add up all the like terms, in this case, the x ones

-20x + 6x = -14x

then, your answer would be:

8x² - 14x - 15