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Liula [17]
3 years ago
9

What is paper chromatography?

Chemistry
1 answer:
ANEK [815]3 years ago
4 0
<span> an analytical method used to separate colored chemicals or substances.</span>
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A solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water. The molar mass of Cu is 63.55 g/mol the molar mass of S
8_murik_8 [283]

Answer:

0.87708moldm-3

Explanation:

molar \: mass \: of \: cuso4 = 63.55 + 32.07 + 4(16.00) \\  =159.62gmol {}^{ - 1}   \\ mole(n) =  \frac{mass}{molar \: mass }  \\ n =  \frac{35}{159.62}  \\ n = 0.21927mol \\ molarity =  \frac{n}{v}  \\ molarity =  \frac{0.21927}{0.25} \\ molarity = 0.87708moldm {}^{ - 3}

3 0
2 years ago
GIVING BRAINLIEST FOR RIGHT ANSWERS PLS HELP
Anuta_ua [19.1K]

Answer:

Answer: Chemical change; Chemical property of heat of combustion

Explanation:

A physical change is defined as a change in which there is alteration in shape, size etc. No new substance gets formed in these reactions.

Explanation:

4 0
3 years ago
Read 2 more answers
(I NEED THIS ANSWERED ASAP!! WORTH 20 PTS)
Schach [20]
1) Independent variable is the physical properties
2) Dependent variable is the pH of the solution.

You can change the physical properties (independent variable) to get a different pH value(dependent variable)
3 0
3 years ago
Read 2 more answers
Which compound has the atom with the highest oxidation number?
kati45 [8]
Answer is: c. MgSO₃.
In magnesium sulfite, magnesium has oxidation number +2, sulfur has oxidatidion number +4 and oxygen -2:
+2 + (+4) + 3·(-2) =0.
a) in calcium sulfide, calcium has oxidation number +2 and sulfur -2:
+2 + (-2) = 0.
b) in sodium nitride, sodium has oxidation number +1 and nitrogen -3:
3 · (+1) + (-3) = 0.
d) in aluminium nitrite, aluminium has oxidation number +3, nitrogen +3 and oxygen has -2:
+3 + (+3 + 2 · (-2)) · 3 = 0.
8 0
3 years ago
What is the solution's freezing point: 15 g of CH4N2O (Molar mass = 60.055 g/mol) in 200. g of H2O? (Kf = 1.86 (°C·kg)/mol)
AURORKA [14]

Ok to answer this question we firsst need to fin the number of mol of Urea (CH4N2O). to do this we simply :

1 mol of urea =15/60.055 = 0.25mol

therefore 200g of water contain 0.25mol

the next step is to determine the malality of our solution in 200g of water, to do this we say:

200 g = 1Kg/1000g = 0.2kg

therefor 0.25mol/0.2Kg = 1.25mol/kg

and from the equation:

we know that i = 1

we are given Kf

b is the molality that we just calculated

therefore;

the solutions freezing point is -2.325°C

8 0
2 years ago
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