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sasho [114]
3 years ago
13

Which compound has the atom with the highest oxidation number?

Chemistry
1 answer:
kati45 [8]3 years ago
8 0
Answer is: c. MgSO₃.
In magnesium sulfite, magnesium has oxidation number +2, sulfur has oxidatidion number +4 and oxygen -2:
+2 + (+4) + 3·(-2) =0.
a) in calcium sulfide, calcium has oxidation number +2 and sulfur -2:
+2 + (-2) = 0.
b) in sodium nitride, sodium has oxidation number +1 and nitrogen -3:
3 · (+1) + (-3) = 0.
d) in aluminium nitrite, aluminium has oxidation number +3, nitrogen +3 and oxygen has -2:
+3 + (+3 + 2 · (-2)) · 3 = 0.
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When the pressure that a gas exerts on a sealed container changes from 1100 bar to 75.5 bar, the temperature changes from k to 2
Serjik [45]
Gay-Lussac's law gives the relationship between pressure and temperature of gas. For a fixed amount of gas, pressure is directly proportional to temperature at constant volume.
P/T = k
where P - pressure , T - temperature and k - constant
\frac{P1}{T1} =  \frac{P2}{T2}
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
substituting the values in the equation 
\frac{1100 bar}{T}  =  \frac{75.5 bar}{298 K}
T = 4342 K
initial temperature was 4342 K
7 0
4 years ago
How many molecules of propane were in the erlenmeyer flask? Avogadro's number is 6. 022 × 10^23 molecules/mol
Ede4ka [16]

3.74×10^{21}

3.74 ×10^{21} molecules of propane were in the erlenmeyer flask.

number of moles of propane can be calculated as moles of propane.

mass of propane =  0.274 g

molar mass of propane = 44.1

So this gives us the value of 6.21×10^{-3} moles of propane

No one mole of propane As a 6.0-2 × 10^{23}

so, 6.21 ×10^{-3} × 6. 022 × 10^23

= 3.74 ×10^{21}

Therefore, molecules of propane were in the erlenmeyer flask is found to be 3.74 ×10^{21}

<h3>What is erlenmeyer flask?</h3>
  • A laboratory flask with a flat bottom, a conical body, and a cylindrical neck is known as an Erlenmeyer flask, sometimes known as a conical flask or a titration flask.
  • It bears the name Emil Erlenmeyer after the German chemist.

<h3>What purpose does an Erlenmeyer flask serve?</h3>
  • Liquids are contained in Erlenmeyer flasks, which are also used for mixing, heating, chilling, incubating, filtering, storing, and other liquid-handling procedures.
  • For titrations and boiling liquids, their sloped sides and small necks make it possible to whirl the contents without worrying about spills.

To learn more about calculating total molecules visit:

brainly.com/question/8933381

#SPJ4

4 0
2 years ago
What happens to liquid when it releases enough energy
Lelechka [254]
When a liquid releases enough energy<span>. the </span>liquid<span> freezes, changing to a solid.

Hope this answer helps! feel free to ask any additional questions :)</span>
8 0
4 years ago
Read 2 more answers
Calculate the amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C.
qwelly [4]

Answer:

The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

Between heat and temperature there is a direct proportional relationship. The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.

In this case:

  • c= 4.184 \frac{J}{g*C}
  • m= 32 g
  • ΔT= Tfinal - Tinitial= 22°C - 8°C= 14°C

Replacing:

Q= 32 g* 4.184 \frac{J}{g*C} *14 °C

Solving:

Q= 1,874.432 J

<u><em>The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J</em></u>

7 0
3 years ago
A sample of gas has a volume of 100. L at 17 °C and 800. torr. To what temperature must the gas be cooled in order for its volum
Romashka [77]

Answer:

108.81 K

Explanation:

First convert 17 °C to Kelvin:

  • 17 + 273.16 = 290.16 K

Assuming ideal behaviour, we can solve this problem by using the<em> combined gas law</em>, which states that at constant composition:

  • P₁V₁T₂=P₂V₂T₁

Where in this case:

  • P₁ = 800 torr
  • V₁ = 100 L
  • T₂ = ?
  • P₂ = 600 torr
  • V₂ = 50 L
  • T₁ = 290.16 K

We <u>input the data</u>:

  • 800 torr * 100 L * T₂ = 600 torr * 50 L * 290.16 K

And <u>solve for T₂</u>:

  • T₂ = 108.81 K
6 0
3 years ago
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