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olchik [2.2K]
2 years ago
10

GIVING BRAINLIEST FOR RIGHT ANSWERS PLS HELP

Chemistry
2 answers:
BigorU [14]2 years ago
5 0

Answer:

: Chemical change; Chemical property of heat of combustion

Explanation:

A physical change is defined as a change in which there is alteration in shape, size etc. No new substance gets formed in these reactions.

Example: Melting of ice

Physical property is defined as the property of a substance which becomes evident during physical changes. Example: Melting point

A chemical change is defined as a change in which a change in chemical composition takes place. A new substance is formed in these reactions.

Example: combustion

Chemical property is defined as the property of a substance which becomes evident during chemical changes. Example: Reactivity with other substances

Thus when a piece of coal and a piece of wood is burnt , there is formation of new substances and thus is a chemical change. Combustion is a chemical property as it is reactivity of a substance with oxygen.

eddibear3a and 18 more users found this answer helpful

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Anuta_ua [19.1K]2 years ago
4 0

Answer:

Answer: Chemical change; Chemical property of heat of combustion

Explanation:

A physical change is defined as a change in which there is alteration in shape, size etc. No new substance gets formed in these reactions.

Explanation:

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A mixture of water and graphite is heated to 600 K in a 1 L container. When the system comes to equilibrium it contains 0.17 mol
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Answer:

0.44 moles

Explanation:

Given that :

A mixture of water and graphite is heated to 600 K in a 1 L container. When the system comes to equilibrium it contains 0.17 mol of H2, 0.17 mol of CO, 0.74 mol of H2O, and some graphite.

The equilibrium constant K_c=  \dfrac{[CO][H_2]}{[H_2O]}

The equilibrium constant  K_c=  \dfrac{(0.17 )(0.17)}{0.74}

The equilibrium constant K_c=  0.03905

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The equation for the reaction is :

H_2 + \dfrac{1}{2}O_2 \to H_2O \\ \\ 0.17 \ \ \ \ \  \ \ \ \ \to0.17

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Total mole of water now = 0.91 moles

Again:

K_c=  \dfrac{[CO][H_2]}{[H_2O]}

0.03905 =  \dfrac{[0.17+x][x]}{[0.91 -x]}

0.03905(0.91 -x) = (0.17 +x)(x)

0.0355355 - 0.03905x = 0.17x + x²

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= 0.17 + x

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= 0.435 moles

=0.44 moles (to two significant figures)

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