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olchik [2.2K]
3 years ago
10

GIVING BRAINLIEST FOR RIGHT ANSWERS PLS HELP

Chemistry
2 answers:
BigorU [14]3 years ago
5 0

Answer:

: Chemical change; Chemical property of heat of combustion

Explanation:

A physical change is defined as a change in which there is alteration in shape, size etc. No new substance gets formed in these reactions.

Example: Melting of ice

Physical property is defined as the property of a substance which becomes evident during physical changes. Example: Melting point

A chemical change is defined as a change in which a change in chemical composition takes place. A new substance is formed in these reactions.

Example: combustion

Chemical property is defined as the property of a substance which becomes evident during chemical changes. Example: Reactivity with other substances

Thus when a piece of coal and a piece of wood is burnt , there is formation of new substances and thus is a chemical change. Combustion is a chemical property as it is reactivity of a substance with oxygen.

eddibear3a and 18 more users found this answer helpful

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Anuta_ua [19.1K]3 years ago
4 0

Answer:

Answer: Chemical change; Chemical property of heat of combustion

Explanation:

A physical change is defined as a change in which there is alteration in shape, size etc. No new substance gets formed in these reactions.

Explanation:

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<u><em>This answer assumes that the strated "16.0g of iron" was meant to be 16.0 grams of iron(III) oxide.</em></u>

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<u>Which of the two reactants is the limiting reagent?</u>

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<u><em>Calculate the maximum mass of iron of iron that could be formed using these quantities of reactants.</em></u>

The balanced equation tells us that we will obtain 2 moles of Fe for every 1 mole of Fe2O3 consumed.  Since Fe2O3 is the limiting reagent, we will assume that it completely reacts.  That means 0.1 moles of Fe2O3 is reacted.  Since we expect twice that many moles of Fe, we should obtain 0.200 moles of Fe.  At 55.85 g/mole, we should obtain:

(0.200 moles Fe)*(55.85 g Fe/mole Fe) = 11.2 grams Fe

<em></em>

<em></em>

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2 years ago
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