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pantera1 [17]
2 years ago
8

A solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water. The molar mass of Cu is 63.55 g/mol the molar mass of S

is 32.07 g/mol, and the molar mass of O is 16.00 g/mol. What is the molarity of the solution?
Chemistry
1 answer:
8_murik_8 [283]2 years ago
3 0

Answer:

0.87708moldm-3

Explanation:

molar \: mass \: of \: cuso4 = 63.55 + 32.07 + 4(16.00) \\  =159.62gmol {}^{ - 1}   \\ mole(n) =  \frac{mass}{molar \: mass }  \\ n =  \frac{35}{159.62}  \\ n = 0.21927mol \\ molarity =  \frac{n}{v}  \\ molarity =  \frac{0.21927}{0.25} \\ molarity = 0.87708moldm {}^{ - 3}

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3 years ago
What was the plum pudding atomic model
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3 years ago
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6 0
3 years ago
Calculate the equilibrium constant at 25 ∘C for the reaction Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)
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Fe2+(aq)+2e−→Fe(s)     E∘= −0.45 V

Ag+aq)+e−→Ag(s)         E∘= 0.80 V

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