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pantera1 [17]
2 years ago
8

A solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water. The molar mass of Cu is 63.55 g/mol the molar mass of S

is 32.07 g/mol, and the molar mass of O is 16.00 g/mol. What is the molarity of the solution?
Chemistry
1 answer:
8_murik_8 [283]2 years ago
3 0

Answer:

0.87708moldm-3

Explanation:

molar \: mass \: of \: cuso4 = 63.55 + 32.07 + 4(16.00) \\  =159.62gmol {}^{ - 1}   \\ mole(n) =  \frac{mass}{molar \: mass }  \\ n =  \frac{35}{159.62}  \\ n = 0.21927mol \\ molarity =  \frac{n}{v}  \\ molarity =  \frac{0.21927}{0.25} \\ molarity = 0.87708moldm {}^{ - 3}

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attashe74 [19]
The answer to this is solved through stochiometry: the answer is  this: 0.0833mol

6 0
3 years ago
You have cyclohexene, water, cyclohexanol, and a little sulfuric acid catalyst in a test tube at 60 oC and everything is at equi
Anvisha [2.4K]

Answer:

See explanation

Explanation:

We can convert cyclohexanol to cyclohexene in the presence of a strong acid such as sulfuric acid catalyst in a test tube at 60 oC by heating up the mixture to about 80 oC. This is a dehydration reaction so water is removed  to yield the alkene. A drying agent is used to remove any trace amount of water left in the system. This overall reaction is endothermic.

Also, the reverse is the case when we want to carry out the hydration of cyclohexene to yield cyclohexanol. The overall reaction is exothermic and involves the addition of more water to the alkene and then cooling down the system to about 40 oC.

8 0
2 years ago
5.(06.04B MC)
NARA [144]

Answer:

Explanation:

1. The reaction will proceed backward, shifting the equilibrium position to the left.

2. The reaction will proceed forward, shifting the equilibrium position to the right.

3. Either add more of the products ( H2O or Cl2) or remove the reactant (HCl or O2)

7 0
2 years ago
For the reactions system 2H2(g) + S2(g) 2H2S(g), a 1.00 liter vessel is found to contain 0.50 moles of H2, 0.020 moles of S2, an
Mnenie [13.5K]

Answer: 1) 2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)

Equilibrium constant is defined as the ratio of the product of concentration of products to the product of concentration of reactants each term raised to their stochiometric coefficients.

K_{eq}=\frac{[H_2S]^2}{H_2]^2\times [S_2]}

where [] = concentration in Molarity=\frac{moles}{\text {Volume in L}}

Thus [H_2S]=\frac{68.5}{1.0}=68.5M

[H_2]=\frac{0.50}{1.0}=0.50M

[S_2]=\frac{0.020}{1.0}=0.020M

K_{eq}=\frac{[68.5]^2}{0.50]^2\times [0.020]}=938450

As the value of K is greater than 1, the reaction is product favored.

2) N_2O_4(g)\rightleftharpoons 2NO_2(g)

K_{eq}=\frac{[NO_2]^2}{[N_2O_4]}

K_{eq}=\frac{[0.500]^2}{[0.0250]}=10

3) N_2+3H_2\rightleftharpoons 2NH_3

K_{eq}=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}

4) Reactions which do not continue to completion are called equilibrium reactions as the rate of forward reaction is equal to the rate of backward direction.


3 0
3 years ago
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