Question

A solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water. The molar mass of Cu is 63.55 g/mol the molar mass of S is 32.07 g/mol, and the molar mass of O is 16.00 g/mol. What is the molarity of the solution?

Answer 1

Answer:

0.87708moldm-3

Explanation:

$molar \: mass \: of \: cuso4 = 63.55 + 32.07 + 4(16.00) \\ =159.62gmol {}^{ - 1} \\ mole(n) = \frac{mass}{molar \: mass } \\ n = \frac{35}{159.62} \\ n = 0.21927mol \\ molarity = \frac{n}{v} \\ molarity = \frac{0.21927}{0.25} \\ molarity = 0.87708moldm {}^{ - 3}$