The skateboarder in the drawing starts down the left side of the ramp with an initial speed of 5.4 m/s. Neglect nonconservative
1 answer:
Answer:
1.5 m
Explanation:
Using the law of conservation of energy
Gain in potential energy by the skateboarder= Loss in kinetic energy by the skateboarder
PE=KE where KE represent potential energy, PE represent potential energy
where m is mass of skateboarder and v is velocity of skateboarder
PE=mgh where m is the mass of skateboarder, g is acceleration due to gravity which in this case is taken as and h is the highest point reached by the skateboarder. Equating PE=KE we have
and since m are on both LHS and LHS, the cancel
} and making h the subject of the above formula
Substituting v with 5.4 m/s and g as we obtain
Rounded off, h=1.5 m
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Heat required to raise the temperature of a given system is
here we know that
m = mass
s = specific heat capacity
= change in temperature
now as we know that
mass of wood = 5 kg
mass of aluminium pan = 2 kg
change in temperature = 45 - 20 = 25 degree C
specific heat capacity of wood = 1700 J/kg C
specific heat capacity of aluminium = 900 J/kg C
now here we will find the total heat to raise the temperature of both
So heat required to raise the temperature of the system is 257500 J
Answer:
4
Explanation:
The kilogram-meter per second (kg · m/s or kg · m · s -1 ) is the standard unit of momentum . Reduced to base units in the International System of Units ( SI ), a kilogram-meter per second is the equivalent of a newton-second (N · s), which is the SI unit of impulse .
