The brakes in a car increase in temperature by ΔT when bringing the car to rest from a speed v. How much greater would ΔT be if
the car initially had twice the speed? You may assume the car to stop sufficiently fast so that no heat transfers out of the brakes.\
1 answer:
Answer:
T would be two times the temperature That it was before the double so if the initial temperature was 20 it would now be 40
Explanation:
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Explanation:
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Vf=0m/s stop speed
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----------------
Use equation for acceleration :
a=(Vf-Vs)/t
a*t=Vf-Vs
t=(Vf-Vs)/a
t=(0-36)/-6
t=-36/-6
t=6 s
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