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Rus_ich [418]
3 years ago
13

The brakes in a car increase in temperature by ΔT when bringing the car to rest from a speed v. How much greater would ΔT be if

the car initially had twice the speed? You may assume the car to stop sufficiently fast so that no heat transfers out of the brakes.\
Physics
1 answer:
Wewaii [24]3 years ago
4 0

Answer:

T would be two times the temperature That it was before the double so if the initial temperature was 20 it would now be 40

Explanation:

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Answer:

The speed is 0.97 c.

Explanation:

Given that,

Dilated time t'= 50.0 years

Rest time t = 13.0 years

We need to calculate the speed

Using formula of time dilation

t'=\dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}}}

Where, t' = change in time

t = rest time

v = velocity

c = speed of light

Put the value into the formula

50.0=\dfrac{13.0}{\sqrt{1-\dfrac{v^2}{(3\times10^{8})^2}}}

v^2=\dfrac{(13)^2\times(c)^2-(c)^2\times50^2}{50^2}

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6 0
3 years ago
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Answer:

35 Joules

Explanation:

Applying

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From the question,

Given: Q = 120 Joules, W = 85 Joules

Substitute these values into equation 2

U = 120-85

U = 35 Joules

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