A proton beam in an accelerator carries a current of 130 μa. if the beam is incident on a target, how many protons strike the ta
1 answer:
The current intensity is the product between the total charge that flows through a certain point (in our case, the target) in a time interval 
:
We know the current,
, and the time interval, 
, so we can find the total charge:
The total charge Q is the product between the number of protons N and the charge of each protons, e, which is
:
we can re-write the equation solving for N, so we can find the number of protons striking the target in 17 s:
We know the current,
The total charge Q is the product between the number of protons N and the charge of each protons, e, which is
we can re-write the equation solving for N, so we can find the number of protons striking the target in 17 s:
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Answer:
A) B = 5.4 10⁻⁵ T, B) the positive side of the bar is to the West
Explanation:
A) For this exercise we must use the expression of Faraday's law for a moving body
fem =
fem = - d (B l y) / dt = - B lv
B =
we calculate
B = - 7.9 10⁻⁴ /(0.73 20)
B = 5.4 10⁻⁵ T
B) to determine which side of the bar is positive, we must use the right hand rule
the thumb points in the direction of the rod movement to the south, the magnetic field points in the horizontal direction and the rod is in the east-west direction.
Therefore the force points in the direction perpendicular to the velocity and the magnetic field is in the east direction; therefore the positive side of the bar is to the West
Answer:
Explanation:
From the question we are told that:
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