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raketka [301]
3 years ago
8

An asteroid revolves around the Sun with a mean orbital radius twice that of Earth’s. Predict the period of the asteroid in Eart

h years.
help
Physics
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0

Answer:

8 years

Explanation:

We can solve the problem by using Kepler's third law, which states that the ratio between square of the orbital period and the cube of the orbital radius of any object revolving around the Sun is constant:

\frac{T_e^2}{r_e^3}=\frac{T_a^2}{r_a^3}

where:

T_e = 1 y is the orbital period of Earth

r_e is the orbital radius of Earth

r_a=2 r_e is the orbital radius of the asteroid (which is twice that of Earth)

T_a = ? is the orbital period of the asteroid

Substituting and re-arranging the equation, we find

T_a^2 = \frac{r_a^3}{r_e^3} T_e^2 = \frac{(2 r_e)^2}{r_e^3} T_e^2=8 \frac{r_e^3}{r_e^3} T_e^2=8 T_e^2 = 8 (1y)^2=8 y

so, the orbital period of the asteroid will be 8 years.

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Answer: Mr. Whitmore would need 7 or more students ( 7.17) to make the box start moving and go outside

Explanation:

Given that;

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2 years ago
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Answer:

   z = 3,737 10⁵ m

Explanation:

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We replace

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3 years ago
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Answer:

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