The scale factor that Ivory used to create their scaled copy is;
<u><em>Scale is 1 interval on graph represents 4 units of the rectangle. This is 1:4 ratio.</em></u>
- From the given image, we can see that the y-axis of the rectangle has 3 intervals while the x-axis has 1 intervals
- Now, from the image, we are told that the area of the scaled copy is 48 square units.
What this means is that the area of the triangle she is trying to represent with that graph is 48 square units.
- Now, if one interval of the graph is x-units, then it means;
length; y-axis = 3x units
width; x-axis = x units
- Area of a rectangle is given by;
Area = Length × width
Thus;
3x * x = 48
3x² = 48
x² = 48/3
x² = 16
x = √16
x = 4
<em>Thus, 1 interval on the graph represents 4 units of the rectangle.</em>
Read more at; brainly.com/question/17182684
Answer:It is given that Joe was being exposed to an electromagnet shrinking machine. Because of this his height started decreasing .
Given,
The decrease was at a constant rate per second.
In 1.5sec, the height is decreased by 120cm.
So,
Variation per second =
Change in each second would be with negative sign indicate's decrease .
Hence, Answer is “-80” .
Step-by-step explanation:
Answer:
(28) 61.5, or $61,500
(29) 49.25, or $49,250
(30) the median
Step-by-step explanation:
(28) the mean can be calculated by adding together the values and then dividing by the total number of values.
(45 + 47 + 47.5 + 51 + 53.5 + 125) / 6 = 61.5
(29) the median can be calculated by crossing off the values from the outside in, alternating sides
45, 47, 47.5, 51, 53.5, 125
47, 47.5, 51, 53.5
47.5, 51
you will end with two middle values since there are six values in the set, so average these to find the median
(47.5 + 51) / 2 = 49.25
(30) The median will better reflect the value of the homes because it is not as much influenced by the outlier value, 125, as the mean is.
Answer:
for problem 1: -4 x -2 = -6
for problem 2: -8x +3 = -11x
Step-by-step explanation:
I hope it helped
brainlest please

First factor out the common x
Then you can use the quadratic equation to solve for the second order polynomial.