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aivan3 [116]
3 years ago
12

Hi I really would like somhelp with this answer I’m stuck on this !! Please answer ASAP

Mathematics
1 answer:
Marina86 [1]3 years ago
8 0

1. Given that we have 4 green marbles, 4 pink marbles and 5 orange marbles, let us first find the probability that we select a pink marble.

We can find this by taking the number of pink marbles and dividing it by the total number of marbles:

Pr(P) = 4/(4 + 4 + 5)

= 4/13

2. Now that we have chosen one pink marble, we must find the probability that we choose an orange marble from the remaining marbles (4 green, 3 pink, 5 orange):

Pr(O) = 5/(4 + 3 + 5)

= 5/12

3. If we want to find the probability of picking a pink marble and then an orange marble, we must multiply the probabilities we have found in the first two steps:

Pr(P)*Pr(O) = (4/13)*(5/12)

= 20/156

= 5/39

Therefor, there is a probability of 5/39 that you pick a pink and then an orange marble.

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2x+20=3x-15

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Use Lagrange multipliers to find the volume of the largest rectangular box in the first octant with three faces in the coordinat
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Answer:

The volume of the largest rectangular box (V) = 81/4

Step-by-step explanation:

<u>Step 1</u>:-

Given volume of the largest rectangular box in the first octant

V = l b h

let (x ,y, z) be the one vertex in the given plane

V = f(x, y, z) = x y z

given plane.   Ф (x, y, z) = x + 9y + 4z = 27 ........(1)

<u>Step( ii):</u>

By using  Lagrange multipliers

Suppose it is required to find the extreme for the function f(x, y, z) subject to the condition Ф (x, y, z) =0

Form Lagrange function F(x, y, z) = f(x, y, z) + λ  Ф (x, y, z) where λ is called the Lagrange multipliers

F(x, y, z) = x y z+ λ ( x + 9y + 4z - 27) ......(2)

Obtain the equations are δ F / δ x = 0

                                  δ f / δ x +λ  δ Ф  / δ x =0

                           ⇒ y z + λ ( 1) = 0

                          ⇒ y z = - λ ......(a)

Obtain the equations are δ F / δ y = 0

                            δ f / δ x +λ  δ Ф  / δ x =0

                        ⇒ x z + λ ( 9) = 0

                        ⇒ \frac{xz}{9} = - λ .......(b)

Obtain the equations are δ F / δ z = 0

                                  δ f / δ x +λ  δ Ф  / δ z =0

                                   x y + λ ( 4) = 0

                                    ⇒ \frac{xy}{4} = - λ .......(c)

<u>Step (iii):-</u>

Equating (a) and (b) equations

we get         y z = \frac{xz}{9}

cancel 'z' value we get  x = 9y  .......(d)

Equating (b) and (c) equations

we get     \frac{xy}{4}  = \frac{xz}{9}

cancel 'x' value on both sides , we get

              4z =9y  ......(e)

substitute (d) (e) values in equation (1)  we get

x + 9y + 4z -27 = 0

9y + 9y + 9y -27 =0

27y -27 =0

<u> y = 1</u>

substitute y =1 in x = 9y

<u>x = 9</u>

substitute y =1 in 4z =9y

<u>z = 9 /4</u>

therefore the dimensions are x =9 , y=1 and z = 9 /4

<u>Conclusion</u>:-

The largest volume of the rectangular box V = x y z

substitute x =9 , y=1 and z = 9 /4

V = 9(1)(9/4) =81/4

The largest volume of the rectangular box (V) = 81/4

Verification :-

Given plane x + 9y + 4z = 27

substitute x =9 , y=1 and z = 9 /4

              9 + 9 + 4(9/4) = 27

           27 =27

so satisfied equation

     

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